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On 3/13/2025 9:48 PM, olcott wrote:void DDD()On 3/13/2025 4:21 PM, Richard Heathfield wrote:Right, because changing the code of HHH1 doesn't change the input.On 13/03/2025 20:48, dbush wrote:>On 3/13/2025 4:46 PM, olcott wrote:>On 3/13/2025 4:27 AM, joes wrote:>Am Wed, 12 Mar 2025 21:41:34 -0500 schrieb olcott:>On 3/12/2025 7:56 PM, dbush wrote:>On 3/12/2025 8:41 PM, olcott wrote:>>>
NOT WHEN IT IS STIPULATED THAT THE BEHAVIOR BEING MEASURED IS
The direct execution of DDD
is proven to be different than the behavior of DDD emulated by HHH
according to the semantics of the x86 language.
Which is weird, considering that a simulator should produce the same
behaviour.
>
>DECIDERS ARE REQUIRED TO REPORT ON THE SEMANTIC OR SYNTACTIC PROPERTY OFAnd not if the input called a different simulator that didn't abort.
THEIR INPUT FINITE STRINGS.
>
Replacing the code of HHH with an unconditional simulator and subsequently running HHH(DD) cannot possibly
reach its own final state no matter what HHH
does.
>
Replacing the code of HHH1 with an unconditional simulator and subsequently running HHH1(DD) does reach its
own final state.
>
If someone was not a liar they would say that
these are different computations.
>
Only because one changes the code that DD runs and one doesn't
It hardly matters. Either his emulation faithfully and correctly establishes and reports (for EVERY program anyone cares to feed it) the actual halting behaviour exhibited by the program it's emulating, or it doesn't.
>
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
>
That everyone expects the behavior of the directly
executed DDD to be the same as DDD correctly emulated
by HHH1 is verified as a factually correct expectation.
>You only think that because you don't understand that changing the code of HHH changes DDD. Changing the input is not allowed.
That everyone expects the behavior of the directly
executed DDD to be the same as DDD correctly emulated
by HHH is verified as a factually incorrect expectation.
>
It is very common for people to be so well indoctrinatedYou don't have the same machine. You just can't see that.
that they reject verified facts out-of-hand without review.
>If it doesn't, it doesn't, and it's a lot of fuss over nothing.>
>
But if it /does/, then we're right back at Turing's proof, because a working emulator is just another way of running the code, and is therefore superfluous to requirements. It adds nothing to the debate, because we can just run the code and get the same answer the emulator would provide.
>
For the first time in the history of mankind it proves
that a simulation of a virtual machine according to
the semantics of this machine language
DOES NOT ALWAYS HAVE THE SAME BEHAVIOR AS THE DIRECT
EXECUTION OF THIS SAME MACHINE
And what you forget is that we're not asking what HHH is able to simulate. We're asking what DDD does when it's executed directly. That HHH attempts to use simulation doesn't change that.
>And the behavior of the input is specified by the specification:
PATHOLOGICAL SELF REFERENCE DOES CHANGE SEMANTICS
PATHOLOGICAL SELF REFERENCE DOES CHANGE SEMANTICS
PATHOLOGICAL SELF REFERENCE DOES CHANGE SEMANTICS
PATHOLOGICAL SELF REFERENCE DOES CHANGE SEMANTICS
>
"This sentence is not true"
is neither true nor false because of PSR
>
This sentence is not true: "This sentence is not true"
The exact same word-for-word sentence
IS TRUE IN THIS DIFFERING CONTEXT THAT DOES NOT HAVE PSR.
>In other words, the emulator is a canard, a distraction, a cul-de- sac, and a complete waste of time. If it happens to work, great! Well done that man. But it doesn't affect the HP logic one microscopically minuscule millijot.>
>
The emulator proves the actual behavior specified by the
INPUT INPUT INPUT INPUT INPUT
Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:
A solution to the halting problem is an algorithm H that computes the following mapping:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly
>The semantics of the x86 language says that when the input to HHH(DDD) is actually run on an actual x86 processor that it will halt.
That people disagree with the semantics of the x86 language
proves how deeply indoctrinated they are.
>
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