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On 3/20/2025 8:31 PM, Richard Damon wrote:You are right. But you can't figure out how to avoid that.On 3/20/25 6:43 PM, olcott wrote:We have been over this same thing too many times.On 3/20/2025 4:16 AM, Mikko wrote:Then HHH isn't a specific program, and you are admitting that you "logic" is just based on FRAUD.On 2025-03-20 02:32:43 +0000, olcott said:N in this context always means any element of the
DDD()That does not make much sense to define the correct emulation of DDD as
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
When N steps of DDD are emulated by HHH according
to the semantics of the x86 language then these
N steps are emulated correctly.
it should mean whatever "correct emulation" means when applied to DDD.
Althouth promised otherwise on the subject line the meaning of "DDD
correctly emulated by HHH" when N is not specified is not defined.
set of natural numbers.
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