Liste des Groupes | Revenir à c theory |
Am Tue, 06 May 2025 13:40:16 -0500 schrieb olcott:It is the exact same HHH/DD pair except that thisOn 5/6/2025 10:53 AM, joes wrote:Then it is not the same HHH.Am Tue, 06 May 2025 10:29:59 -0500 schrieb olcott:>On 5/6/2025 4:35 AM, Mikko wrote:>On 2025-05-05 17:37:20 +0000, olcott said:As agreed to below:The above example is category error because it asks HHH(DD) to>
report on the direct execution of DD() and the input to HHH
specifies a different sequence of steps.
No, it does not. The input is DD specifides exactly the same sequence
of steps as DD. HHH just answers about a different sequence of steps
instead of the the seqeunce specified by its input.
><MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D *would never
stop running unless aborted* then
>
*input D* is the actual input *would never stop running unless
aborted* is the hypothetical H/D pair where H does not abort.H should simulate its actual input D that calls the aborting H, not a*would never stop running unless aborted*
hypothetical version of D that calls a pure simulator.
>
refers to the same HHH that DD calls yet this hypothetical HHH does not
abort.
>You cannot possibly show the exact execution trace where DD is
correctly emulated by HHH and this emulated DD reaches past its own
machine address [0000213c].Duh, no simulator can simulate itself correctly. But HHH1 can simulateHHH does simulate itself correctly yet must create a separate process
DD/HHH.
context for each recursive emulation.
Each process context has its own stack and set of virtual registers.
No, HHH simulates only one program.HHH correctly emulates DD and correctly emulates itself
Les messages affichés proviennent d'usenet.