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On 09/05/2025 21:15, olcott wrote:Any competent C programmer can see thatOn 5/9/2025 3:07 PM, Richard Heathfield wrote:I haven't touched your words. What I have done is to observe that DDD's /only/ action is to call a simulator. Since DDD isn't itself a simulator, there is nothing to simulate except a call to a simulator.On 09/05/2025 20:46, olcott wrote:>We have not begun to get into any of those points.>
We are only asking can DDD correctly simulated
by any HHH that can exist ever reach its own
"return" instruction.
DDD can't be correctly simulated by itself (which is effectively what you're trying to do when you fire up the simulation from inside DDD).
>
How the Hell did you twist my words to say that?
It's recursion without a base case - a rookie error.
HHH cannot successfully complete its task, because it never regains control after the first recursion. To return, it must abort the simulation, which means the simulation fails.
>On what grounds can you persuade an extraordinarily sceptical readership that HHH 'correctly simulated' DDD?
void DDD()
{
HHH(DDD);
return;
}
>
When 1 or more statements of DDD are correctly
simulated by HHH then this correctly simulated
DDD cannot possibly reach its own “return statement”.
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