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On Sun, 11 May 2025 10:56:02 -0500, olcott wrote:That fails to meet the spec of a termination analyzer.
On 5/11/2025 10:49 AM, Mr Flibble wrote:===========================================================================================On Sun, 11 May 2025 16:47:09 +0100, Richard Heathfield wrote:
>On 11/05/2025 16:34, Mr Flibble wrote:>On Sun, 11 May 2025 16:25:14 +0100, Richard Heathfield wrote:>
>For a question to be semantically incorrect, it takes more than just>
you and your allies to be unhappy with it.
For a question to be semantically correct, it takes more than just
you and your allies to be happy with it.
Indeed. It has to have meaning. It does. That meaning has to be
understood by sufficiently intelligent people. It is.
>
You don't like the question. I get that. I don't know /why/ you don't
like it, because all your explanations to date have been complete
expletive deleted. For a Usenet article to be semantically correct, it
helps if your readers can understand what the <exp. del.> you're
talking about.
>
What I get from your stand is that you agree with olcott that a
'pathological' input halts... no, never halts... well, you can't
decide between you, but you're agreed that it's definitely decidable,
right?
Re-read the OP for my answer:
>
Flibble’s Leap: Why Behavioral Divergence Implies a Type Distinction in
the Halting Problem
>That behaviour is due to a decision you have made, that I disagree with,>>
Summary -------
Flibble argues that the Halting Problem's undecidability proof is built
on a category (type) error: it assumes a program and its own
representation (as a finite string) are interchangeable. This
assumption fails under simulating deciders, revealing a type
distinction through behavioral divergence. As such, all deciders must
respect this boundary, and diagonalization becomes ill-formed. This
reframing dissolves the paradox by making the Halting Problem itself an
ill-posed question.
>
1. Operational Evidence of Type Distinction
-------------------------------------------
- When a program (e.g., `DD()`) is passed to a simulating halt decider
(`HHH`), it leads to infinite recursion.
- This behavior differs from direct execution (e.g., a crash due to a
stack overflow).
The directly executed DD() simply halts because HHH has stopped the
infinite recursion that it specifies on its second recursive call.
the correct thing to do is to allow infinite recursion to manifest as
stack overflow rather than return an artificial halting result.
int sum(int x, int y) { return x + y; }>The category error precludes a decision being made as the problem is ill-
DD emulated by HHH according to the rules of the x86 language cannot
possibly halt. Because all deciders are required to report on what their
finite string input specifies HHH must reject DD as non-halting.
formed.
/Flibble
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