Liste des Groupes | Revenir à c theory |
On 5/5/2024 10:42 AM, joes wrote:And if the simultor doesn't simulate enough to actually know the correct answer to the quesition about the behavior of the program described by the input, then it didn't simulate enough.Am Sun, 05 May 2024 09:30:20 -0500 schrieb olcott:That sounds screwy when the input computes factorial(5)
>On 5/5/2024 5:36 AM, Fred. Zwarts wrote:[please snip your replies a little]Op 05.mei.2024 om 05:17 schreef olcott:On 5/4/2024 9:49 PM, Richard Damon wrote:On 5/4/24 9:30 PM, olcott wrote:On 5/4/2024 8:05 PM, Richard Damon wrote:On 5/4/24 8:49 PM, olcott wrote:On 5/4/2024 7:44 PM, Richard Damon wrote:On 5/4/24 8:20 PM, olcott wrote:On 5/4/2024 7:07 PM, Richard Damon wrote:On 5/4/24 7:51 PM, olcott wrote:On 5/4/2024 6:32 PM, Richard Damon wrote:On 5/4/24 7:01 PM, olcott wrote:On 5/4/2024 5:36 PM, Richard Damon wrote:On 5/4/24 6:08 PM, olcott wrote:On 5/4/2024 4:43 PM, Richard Damon wrote:On 5/4/24 5:18 PM, olcott wrote:On 5/4/2024 3:40 PM, Richard Damon wrote:On 5/4/24 2:46 PM, olcott wrote:On 5/4/2024 12:15 PM, Richard Damon wrote:On 5/4/24 12:31 PM, olcott wrote:On 5/4/2024 10:52 AM, Richard Damon wrote:On 5/4/24 10:48 AM, olcott wrote:On 5/4/2024 9:39 AM, Alan Mackenzie wrote:olcott <polcott333@gmail.com> wrote:On 5/4/2024 5:56 AM, Alan Mackenzie wrote:>[ Followup-To: set ]>In comp.theory olcott <polcott333@gmail.com>
wrote:
>>>Those N steps were simulated correctly, but the fact that it stopsNote, you CAN'T just "Stipulate" that a given machine IS a UTM exceptNone-the-less a TM that correctly simulates N steps cannot be said to
by defining that it works just like a UTM, which means, for one
thing, it can NEVER abort its simulation, not even after determining
that it will simulate this input forever.
>
have simulated those N steps incorrectly on the basis that it could
have simulated N+1 steps.
>
after N steps make it an incorrect simulation.
In other words a decider is wrong unless it never stops simulating an
non-halting input?
Correct. Simulating here means producing the exact same behaviour.
If it is correct up to a point, it might still make a mistake later.
The only way to know is to keep simulating.
>
Les messages affichés proviennent d'usenet.