Liste des Groupes | Revenir à c theory |
Op 14.jun.2024 om 14:49 schreef olcott:*CONVENTIONAL TERMINOLOGY*I ran the actual code to verify the facts.Your terminology is confusing. What you call a "pathological relationship" is that H must simulate itself.
HH1(DD,DD) does not have a pathological relationship to its input
thus this input terminates normally.
If the input is never aborted THEN IT NEVER TERMINATES.>Yes, indeed! Well done! The input of HH(DD,DD) is aborted too early,
HH(DD,DD) does have a pathological relationship to its input
thus this input CANNOT POSSIBLY terminate normally.
because HH cannot possibly simulate itself up to its final state. That means that its simulation cannot terminate normally.*It is D that calls H in recursive simulation*
Until H sees that D correctly simulated by H cannot>I understand that very well, a, b, c explain why HH is not able to simulate itself up to the end. You are proving my claims.It is only that H simulated by itself is aborted too early. Is that so difficult to understand for you?Aborted too early is false.
>
Unless HH(DD,DD) aborts pretty soon HH and DD crash due to
out-of-memory error.
>>If H waits for some other H to abort their>
simulation then H waits forever.
There is no other H.
Clearly you hardly understand anything that I have been saying.
(a) HH(DD,DD) directly executed in main simulates its input.
(b) The simulated DD calls a simulated HH(DD,DD) that
(c) simulates another instance of DD... goto (b)
Another way of saying the same thing is:
1) HH starts simulating DD
Les messages affichés proviennent d'usenet.