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On 6/28/2024 2:17 AM, Mikko wrote:Then prove it. The following does not even mention H0 and thereforeOn 2024-06-27 17:07:20 +0000, olcott said:It is not at all too hard to prove.
Until you agree with this we cannot move on to the nextIf it is too hard to prove that H0 has the properties you claim
and final point that proves I am correct. Proving that
point may possibly take longer than the rest of my life
so let's not delay this OK?
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call H0(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
The call from DDD to H0(DDD) when DDD is correctly emulated
by x86 emulator H0 cannot possibly return.
then an agreement is unlikely. Perhaps you should Δ instead and
just assume it has the properties you consider essential. The
full proof of your claim does not need much more.
It is easy to proveThe phrase "any pure function x86 emulator HHH" is incorrect. In particular,
if you know, C, x86 emulators and the x86 language
sufficiently well and impossible otherwise.
https://liarparadox.org/HHH(DDD)_Full_Trace.pdf
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
The call from DDD to HHH(DDD) when N steps of DDD are correctly
emulated by any pure function x86 emulator HHH cannot possibly return.
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