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On 7/2/2024 1:59 AM, Mikko wrote:As long as no proof is shown it is not proven.On 2024-07-01 12:44:57 +0000, olcott said:IT IS PROVEN BY THE SEMANTICS OF THE X86 LANGUAGE
On 7/1/2024 1:05 AM, Mikko wrote:At least you have claimed more than proven.On 2024-06-30 17:18:09 +0000, olcott said:I have never lied about this.Richard just said that he affirms that when DDD correctlyIt is your HHH so you should know whether it returns. Others may
simulated by HHH calls HHH(DDD) that this call returns even
though the semantics of the x86 language disagrees.
On 6/30/2024 7:34 AM, Richard Damon wrote:
> It is still true that the xemantics of the x86
> language define the behavior of a set of bytes,
> as the behavior when you ACTUALLY RUN THEM,
> and nothing else.
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
Richard thinks that he can get away with disagreeing with this
verified fact:
The call from DDD to HHH(DDD) when N steps of DDD are correctly
emulated by any pure function x86 emulator HHH cannot possibly
return.
have wrong impression about it if they have trusted your lies.
_DDD()The correctness remain unproven.
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.
THAT YOU REMAIN WILLFULLY IGNORANT OF SEMANTICS OF
THE X86 LANGUAGE DOES NOT MEAN IT HAS NOT BEEN PROVEN.
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