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On 7/2/2024 11:05 PM, joes wrote:Because it proves you wrong!Am Tue, 02 Jul 2024 21:03:11 -0500 schrieb olcott:Yes but I won't.On 7/2/2024 8:51 PM, Richard Damon wrote:>On 7/2/24 9:32 PM, olcott wrote:On 7/2/2024 8:25 PM, Richard Damon wrote:On 7/2/24 9:18 PM, olcott wrote:Better repent then.You continue to assume that you can simply disagree with the x86
language. My memory was refreshed that called you stupid would be a
sin according to Christ.
>What semantics proves that HHH doesn’t halt?But I am NOT disagreeing with the x86 language.You keep trying to get away with saying that the simulation is incorrect
Can you point out what fact of it I am disagreing about it?
when the semantics of the x86 language conclusively proves that it is
correct.
Can you show the C code where it aborts?
>
Nope, Aborted meaning the emulation stops emulating.Aborted meaning immediately stops running.DDD is emulated by HHH which calls an emulated HHH(DDD)Aborted by HHH, so that it can return.
to repeat this process until the emulated DDD is aborted.
>
At no point in this emulation does the call from DDD correctly emulated
by HHH to HHH(DDD) ever return.Except for the outer call to HHH from main.HHH stops running after aborting its input.
>
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