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On 7/2/2024 11:05 PM, joes wrote:Am Tue, 02 Jul 2024 21:03:11 -0500 schrieb olcott:On 7/2/2024 8:51 PM, Richard Damon wrote:On 7/2/24 9:32 PM, olcott wrote:On 7/2/2024 8:25 PM, Richard Damon wrote:On 7/2/24 9:18 PM, olcott wrote:
That makes a proof a bit tricky.Yes but I won't.What semantics proves that HHH doesn’t halt? Can you show the C codeCan you point out what fact of it I am disagreing about it?
where it aborts?
So that HHH can return.Aborted meaning immediately stops running.DDD is emulated by HHH which calls an emulated HHH(DDD)Aborted by HHH, so that it can return.
to repeat this process until the emulated DDD is aborted.
Does that mean it returns or does it call exit()?HHH stops running after aborting its input.At no point in this emulation does the call from DDD correctlyExcept for the outer call to HHH from main.
emulated by HHH to HHH(DDD) ever return.
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