Re: DDD correctly emulated by HHH is correctly rejected as non-halting.

On 7/12/2024 3:15 AM, Mikko wrote:

On 2024-07-11 14:12:15 +0000, olcott said:
 

On 7/11/2024 1:28 AM, Mikko wrote:

On 2024-07-10 18:58:14 +0000, olcott said:
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On 7/10/2024 1:55 PM, Alan Mackenzie wrote:

Fred. Zwarts <F.Zwarts@hetnet.nl> wrote:

Op 10.jul.2024 om 20:12 schreef Alan Mackenzie:

[ Followup-To: set ]

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In comp.theory Fred. Zwarts <F.Zwarts@hetnet.nl> wrote:

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[ .... ]

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Proving that the simulation is incorrect. Because a correct simulation
would not abort a halting program halfway its simulation.

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Just for clarity, a correct simulation wouldn't abort a non-halting
program either, would it?  Or have I misunderstood this correctness?

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[ .... ]

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A non-halting program cannot be simulated correctly in a finite time.
So, it depends whether we can call it a correct simulation, when it does
not abort. But, for some meaning of 'correct', indeed, a simulator
should not abort a non-halting program either.

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OK, thanks!
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In other words he is saying that when you do
1 step correctly you did 0 steps correctly.

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That is possible as "correctly" has different meaning when talking
about steps from when talking about simulations.
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*No that is always false*
When you did one anythings correctly then you did
more than zero anythings correctly.

 If I only correcly do one thing that is not a part of my routine then
I don't do my routine correctly. If I do correctly every part of my routine
but do them in a wrong order I don't do my routine correctly.
 

Fred was trying to get away with saying that when 1
step of DDD is correctly emulated by HHH that 0 steps
were emulated correctly.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer