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On 7/15/2024 3:23 AM, Mikko wrote:That is not an acceptable axiom. That you are unable to prove thatOn 2024-07-14 14:38:31 +0000, olcott said:Weasel words. This is an axiom:
On 7/14/2024 3:09 AM, Mikko wrote:That the input is aborted does not mean that the input must be aborted.On 2024-07-13 20:15:56 +0000, olcott said:*You can comprehend this is a truism or fail to*
typedef void (*ptr)();Everyone understands that DDD specifies a halting behaviour if HHH(DDD) does,
int HHH(ptr P);
void Infinite_Loop()
{
HERE: goto HERE;
}
void Infinite_Recursion()
{
Infinite_Recursion();
}
void DDD()
{
HHH(DDD);
}
int main()
{
HHH(Infinite_Loop);
HHH(Infinite_Recursion);
HHH(DDD);
}
Any input that must be aborted to prevent the non
termination of HHH necessarily specifies non-halting
behavior or it would never need to be aborted.
*comprehend it disagreement is necessarily incorrect*
Any input that must be aborted to prevent the non
termination of HHH necessarily specifies non-halting
behavior or it would never need to be aborted.
Disagreeing with the above is analogous to disagreeing
with arithmetic.
Input XXX must be aborted to prevent the non-termination of HHH.
From the fact that XXX must be aborted we can conclude that XXX must be aborted.Nothing that contains the word "must" is a fact.
I can't see how you were simply not flat out dishonest.That you cannot do something without being dishoest does not prevent us.
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