Re: This function proves that only the outermost HHH examines the execution trace

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Sujet : Re: This function proves that only the outermost HHH examines the execution trace
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theory
Date : 27. Jul 2024, 04:17:23
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <fa8edcaf947e240fe7895c4e3a89dcb52beb66a1@i2pn2.org>
References : 1
User-Agent : Mozilla Thunderbird
The problem you keep on ignoring is that the behavior of a program is what it does when actually run, and not partially simulated and then aborted.
That fundamental error in you definitions means none of you logic matters.
The fact that DDD calls an HHH(DDD) that will, when called by main the same way, returns to main, means it will return to DDD and thus DDD halts.
Your argument contrary to that just proves you don't understand that emulation is only a means to observe behavior, and doesn't actually define that behavior, especially when it is just a partial emulation.
Fundamentally, you are just proving you are just incapable of understand the difference between the TRUTH of the behavior of DDD, which is established purely by the actual behavor of it code, which neds ALL the code (incuding that of HHH)
That behavior is fully fixed and determined the moment that code is defined. We only know that behavior by running or emulating that code, FULLY.
If HHH returns to main, and is an actual computation, then it returns to DDD and thus DDD WILL HALT. PERIOD.
To claim anything else is to admit that you are a liar or your logic system is just inconsistant, or both.
On 7/26/24 11:56 AM, olcott wrote:
This is meant for Mike, Joes and Fred don't have the technical competence to understand it.
 Richard might be able to understand it yet the fact that he is
stuck in rebuttal mode makes any understanding that he may have
utterly useless.
 Mike: It seems that HHH has been a pure function of its inputs
and never has provided data downward to its slaves that corrupts
their halt status decision. They don't even make a halt status
decision thus cannot make a corrupted one.
 I could change the code so that the slave instances can and do
try to form a halt status decision on the basis of the execution
trace that they do have.
 There is no sense in doing that because they can't possibly have
enough data, they will always be one whole execution trace behind
the next outer instance of HHH.
 As they are the slaves perform their proper function of showing
the actual behavior of DDD correctly emulated by HHH.
 u32 Decide_Halting_HH(u32**                   Aborted,
                       u32**                   execution_trace,
                       Decoded_Line_Of_Code**  decoded,
                       u32                     code_end,
                       u32                     End_Of_Code,
                       Registers**             master_state,
                       Registers**             slave_state,
                       u32**                   slave_stack,
                       u32                     Root)
{
   u32 aborted_temp = 0;  // 2024-06-05
   u32 Current_Length_Of_Execution_Trace = 0;
   while (aborted_temp == 0) // 2024-06-05
   {
     u32 EIP = (*slave_state)->EIP; // Save EIP of this instruction
     DebugStep(*master_state, *slave_state, *decoded); // Execute it
     if (EIP > Last_Address_Of_Operating_System())     // Ignore OS code
     {
       PushBack(**execution_trace, (u32)*decoded,
                sizeof(Decoded_Line_Of_Code));
     }
      if (EIP == code_end)
       return 1;
      if (Root)  // Master UTM halt decider
     {
       u32* address = (u32*)**execution_trace;
       u32 size  = (u32)*(address-1);
       // Detects slave appended an instruction to its execution_trace
       if (size > Current_Length_Of_Execution_Trace)
       {
         Current_Length_Of_Execution_Trace = size;
         aborted_temp =     // 2024-06-05
         Needs_To_Be_Aborted_HH
         ((Decoded_Line_Of_Code*)**execution_trace);
       }
     }
   }
   if (aborted_temp == 1) // 2021-01-26 Must be aborted
     return 0;
   return 1;           // 2021-01-26 Need not be aborted
}
  

Date Sujet#  Auteur
26 Jul 24 * This function proves that only the outermost HHH examines the execution trace112olcott
26 Jul 24 +* Re: This function proves that only the outermost HHH examines the execution trace3joes
26 Jul 24 i`* Re: This function proves that only the outermost HHH examines the execution trace2Mike Terry
26 Jul 24 i `- Re: This function proves that only the outermost HHH examines the execution trace1olcott
26 Jul 24 +* Re: This function proves that only the outermost HHH examines the execution trace50Mike Terry
26 Jul 24 i`* Re: This function proves that only the outermost HHH examines the execution trace49olcott
27 Jul 24 i +* Re: This function proves that only the outermost HHH examines the execution trace4Mikko
27 Jul 24 i i`* Re: This function proves that only the outermost HHH examines the execution trace3olcott
27 Jul 24 i i +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
28 Jul 24 i i `- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
27 Jul 24 i +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
27 Jul 24 i +* Re: This function proves that only the outermost HHH examines the execution trace6Fred. Zwarts
27 Jul 24 i i`* Re: This function proves that only the outermost HHH examines the execution trace5olcott
27 Jul 24 i i +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
27 Jul 24 i i +* Re: This function proves that only the outermost HHH examines the execution trace2joes
27 Jul 24 i i i`- Re: This function proves that only the outermost HHH examines the execution trace1olcott
28 Jul 24 i i `- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
27 Jul 24 i `* Re: This function proves that only the outermost HHH examines the execution trace37Fred. Zwarts
27 Jul 24 i  `* Re: This function proves that only the outermost HHH examines the execution trace36olcott
27 Jul 24 i   +* Re: This function proves that only the outermost HHH examines the execution trace31Fred. Zwarts
27 Jul 24 i   i`* Re: This function proves that only the outermost HHH examines the execution trace30olcott
28 Jul 24 i   i +* Re: This function proves that only the outermost HHH examines the execution trace5Fred. Zwarts
28 Jul 24 i   i i`* Re: This function proves that only the outermost HHH examines the execution trace4olcott
28 Jul 24 i   i i +- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
28 Jul 24 i   i i +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
28 Jul 24 i   i i `- Re: This function proves that only the outermost HHH examines the execution trace1joes
28 Jul 24 i   i `* Re: This function proves that only the outermost HHH examines the execution trace24Mikko
29 Jul 24 i   i  `* Re: This function proves that only the outermost HHH examines the execution trace23olcott
29 Jul 24 i   i   +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
30 Jul 24 i   i   +- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
30 Jul 24 i   i   `* Re: This function proves that only the outermost HHH examines the execution trace20Mikko
31 Jul 24 i   i    `* Re: This function proves that only the outermost HHH examines the execution trace19olcott
31 Jul 24 i   i     +- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
31 Jul 24 i   i     `* Re: This function proves that only the outermost HHH examines the execution trace17Mikko
31 Jul 24 i   i      +* Re: This function proves that only the outermost HHH examines the execution trace14olcott
1 Aug 24 i   i      i`* Re: This function proves that only the outermost HHH examines the execution trace13Mikko
1 Aug 24 i   i      i `* Re: This function proves that only the outermost HHH examines the execution trace12olcott
1 Aug 24 i   i      i  +* Re: This function proves that only the outermost HHH examines the execution trace10Fred. Zwarts
1 Aug 24 i   i      i  i`* Re: This function proves that only the outermost HHH examines the execution trace9olcott
1 Aug 24 i   i      i  i +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
1 Aug 24 i   i      i  i `* Re: This function proves that only the outermost HHH examines the execution trace7joes
1 Aug 24 i   i      i  i  `* Re: This function proves that only the outermost HHH examines the execution trace6olcott
1 Aug 24 i   i      i  i   +* Re: This function proves that only the outermost HHH examines the execution trace3Fred. Zwarts
1 Aug 24 i   i      i  i   i`* Re: This function proves that only the outermost HHH examines the execution trace2olcott
2 Aug 24 i   i      i  i   i `- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
1 Aug 24 i   i      i  i   `* Re: This function proves that only the outermost HHH examines the execution trace2joes
1 Aug 24 i   i      i  i    `- Re: This function proves that only the outermost HHH examines the execution trace1olcott
2 Aug 24 i   i      i  `- Re: This function proves that only the outermost HHH examines the execution trace1Mikko
31 Jul 24 i   i      `* Re: This function proves that only the outermost HHH examines the execution trace2olcott
1 Aug 24 i   i       `- Re: This function proves that only the outermost HHH examines the execution trace1Mikko
28 Jul 24 i   `* Re: This function proves that only the outermost HHH examines the execution trace4Mikko
29 Jul 24 i    `* HHH(Infinite_Recursion) and HHH(DDD) derive same non-halting execution trace3olcott
29 Jul 24 i     +- Re: HHH(Infinite_Recursion) and HHH(DDD) derive same non-halting execution trace1Fred. Zwarts
30 Jul 24 i     `- Re: HHH(Infinite_Recursion) and HHH(DDD) derive same non-halting execution trace1Mikko
27 Jul 24 +- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
27 Jul 24 +* Re: This function proves that only the outermost HHH examines the execution trace56Fred. Zwarts
27 Jul 24 i`* Re: This function proves that only the outermost HHH examines the execution trace55olcott
27 Jul 24 i `* Re: This function proves that only the outermost HHH examines the execution trace54Fred. Zwarts
27 Jul 24 i  `* Re: This function proves that only the outermost HHH examines the execution trace53olcott
27 Jul 24 i   +* Re: This function proves that only the outermost HHH examines the execution trace50Alan Mackenzie
27 Jul 24 i   i+* Re: This function proves that only the outermost HHH examines the execution trace17olcott
27 Jul 24 i   ii+* Re: This function proves that only the outermost HHH examines the execution trace9Alan Mackenzie
27 Jul 24 i   iii`* Re: This function proves that only the outermost HHH examines the execution trace8olcott
27 Jul 24 i   iii `* Re: This function proves that only the outermost HHH examines the execution trace7Alan Mackenzie
27 Jul 24 i   iii  `* Re: This function proves that only the outermost HHH examines the execution trace6olcott
27 Jul 24 i   iii   `* Re: This function proves that only the outermost HHH examines the execution trace5Alan Mackenzie
28 Jul 24 i   iii    `* Re: This function proves that only the outermost HHH examines the execution trace4olcott
28 Jul 24 i   iii     `* Re: This function proves that only the outermost HHH examines the execution trace3Alan Mackenzie
28 Jul 24 i   iii      `* Re: This function proves that only the outermost HHH examines the execution trace2olcott
28 Jul 24 i   iii       `- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
28 Jul 24 i   ii`* Re: This function proves that only the outermost HHH examines the execution trace7Mikko
29 Jul 24 i   ii `* Re: This function proves that only the outermost HHH examines the execution trace6olcott
29 Jul 24 i   ii  +- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
29 Jul 24 i   ii  `* Re: This function proves that only the outermost HHH examines the execution trace4Mikko
29 Jul 24 i   ii   `* Re: This function proves that only the outermost HHH examines the execution trace3olcott
29 Jul 24 i   ii    +- Re: This function proves that only the outermost HHH examines the execution trace1Fred. Zwarts
30 Jul 24 i   ii    `- Re: This function proves that only the outermost HHH examines the execution trace1Mikko
28 Jul 24 i   i+* Re: This function proves that only the outermost HHH examines the execution trace27Mike Terry
28 Jul 24 i   ii+- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
28 Jul 24 i   ii+* Re: This function proves that only the outermost HHH examines the execution trace21olcott
28 Jul 24 i   iii+- Re: This function proves that only the outermost HHH examines the execution trace1Richard Damon
28 Jul 24 i   iii`* Re: This function proves that only the outermost HHH examines the execution trace19Fred. Zwarts
28 Jul 24 i   iii `* HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)18olcott
28 Jul 24 i   iii  +- Re: HHH(DDD) does not see the exact same behavior pattern as HHH(Infinite_Recursion)1Richard Damon
28 Jul 24 i   iii  `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)16Fred. Zwarts
28 Jul 24 i   iii   `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)15olcott
28 Jul 24 i   iii    +- Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion) unless it can abort.1Richard Damon
29 Jul 24 i   iii    `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)13Fred. Zwarts
29 Jul 24 i   iii     `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)12olcott
29 Jul 24 i   iii      `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)11Fred. Zwarts
30 Jul 24 i   iii       `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)10Mike Terry
30 Jul 24 i   iii        `* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)9olcott
30 Jul 24 i   iii         +- Re: HHH(DDD) does not see the exact same behavior pattern as HHH(Infinite_Recursion) OLCOTTS ERROR1Richard Damon
30 Jul 24 i   iii         +* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)6joes
31 Jul 24 i   iii         i`* Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)5Mike Terry
31 Jul 24 i   iii         i `* Linz proof is essentially isomorphic4olcott
31 Jul 24 i   iii         i  `* Re: Linz proof is essentially isomorphic3Richard Damon
31 Jul 24 i   iii         i   `* Re: Linz proof is essentially isomorphic2olcott
31 Jul 24 i   iii         i    `- Re: Linz proof is essentially isomorphic1Richard Damon
30 Jul 24 i   iii         `- Re: HHH(DDD) sees the exact same behavior pattern as HHH(Infinite_Recursion)1Fred. Zwarts
28 Jul 24 i   ii`* Re: This function proves that only the outermost HHH examines the execution trace4Alan Mackenzie
28 Jul 24 i   i`* Re: This function proves that only the outermost HHH examines the execution trace5Mikko
27 Jul 24 i   `* Re: This function proves that only the outermost HHH examines the execution trace2Fred. Zwarts
3 Aug 24 `- Re: This function proves that only the outermost HHH examines the execution trace1Mikko

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