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On 8/7/2024 3:16 AM, Fred. Zwarts wrote:No, YOU youse an incorrect criteria of correct, as you don't correctly emulatin the instruction, after all, you have failed ot EVER show a trace produced by HHH of its emulation of its input that show it emulation the instructions at the target of the Call HHH InstructionOp 04.aug.2024 om 15:11 schreef olcott:*According to an incorrect criteria of correct*On 8/4/2024 1:26 AM, Fred. Zwarts wrote:>Op 03.aug.2024 om 17:20 schreef olcott:>>>When you try to show how DDD simulated by HHH does>
reach its "return" instruction you must necessarily
must fail unless you cheat by disagreeing with the
semantics of C. That you fail to have a sufficient
understanding of the semantics of C is less than no
rebuttal what-so-ever.
Fortunately that is not what I try, because I understand that HHH cannot possibly simulate itself correctly.
>
void DDD()
{
HHH(DDD);
return;
}
>
In other words when HHH simulates itself simulating DDD it
is supposed to do something other than simulating itself
simulating DDD ??? Do you expect it to make a cup of coffee?
>
Is English too difficult for you. I said HHH cannot do it correctly.
You keep trying to get away with disagreeing with
the semantics of the x86 language. *That is not allowed*
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