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On 8/13/2024 6:23 AM, Richard Damon wrote:No, it just takes an infinite number of steps, and thus doesn't complete in FINITE time.On 8/12/24 11:45 PM, olcott wrote:A complete emulation of a non-terminating input has alwaysOn 8/12/2024 10:09 PM, Mike Terry wrote:>On 12/08/2024 22:13, Richard Damon wrote:>On 8/12/24 2:25 PM, olcott wrote:>On 8/12/2024 1:16 PM, Richard Damon wrote:>On 8/12/24 1:32 PM, olcott wrote:On 8/12/2024 12:12 PM, Richard Damon wrote:YOU don't understand the rules of the x86 code, or don't care if you are wrong, as NOTHING in the x86 language allows the leaving of the direct exectuion thread and into showing the code the simulator being simulated is simulating. The ONLY correct answer is showing it doing the simulating.>
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I showed the first four lines of this code
highlighted in red and you ignored it.
https://liarparadox.org/HHH(DDD)_Full_Trace.pdf
First a few comments about this file.
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It has clearlly changed over time without notice, you said you added highlighting, but it also has had content changes.
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It really needs to be date-stamped and version controlled. I can not say if the copy I look at today is the same as I looked at the other day.
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Second, it is NOT the trace you keep on claiming but is the trace that x86UTM makes of running main, with the trace that the levels of HHH do inserted (WITHOUT COMMENT) into the listing, making the trace that HHH generats hard to find.
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The length of the wrong trace starts on page 38, so there are only about 160 pages of trace (the rest is an assembly listing of the program, useful to understand the trace, but not part of the trace itself) and there are only 1 to 2 lines from HHH per page, so a trace of just what HHH does would be only about 200-300 LINES long, not 200 pages, and not beyond what many people can handle, especially when you remove the cruft of having to wade through all the other junk that isn't the trace that HHH makes.
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There are also clearly functions that are not even correctly listed in the assembly listings, nor traced, that seem to be hooks to make OS calls. That isn't totally unreasonable, but not clearly marked as such.
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>>>>
No, you ignored my comments.
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First, that isn't a trace generated by HHH emulating DDD, but by x86UTM emulating HHH, so your claim is just a type error.
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Then when I look at this emulation, we see that HHH *ONLY* emulates those first 4 instructions of HHH and no more,
That is counter factual.
Looking closer, I may have gotten confused by the changing file by the same name
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I do see the simulation continuing into HHH, but ...
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One thing I do note is that the trace sees conditional jump instructions in the trace, but your "rule" is that there can be no conditional instructions see in the full loop, so something is wrong.
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One instruction I see is:
Page 79, simulated the JNZ 00001335 at address 000012f8
Why wasn't this counted as a conditional instruction in the trace?
(That means the recursion isn't unconditional)
PO's rule is that there must be no conditional branch instructions *WITHIN DDD*. Conditional branch instructions in HHH are simulated, and with suitable compilation options [I think it is the TRACE_USER_CODE_ONLY pre-processing symbol that needs to be undefined] those instructions will also be LOGGED. Well, you're seeing the result of that on page 79 of the PDF file.
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Distinction between what is LOGGED (by x86utm.exe), and what goes into the global trace table examined by HHH: The former is an x86utm ("supervisor?") concept. The latter is HHH application logic - HHH implements the tests for "non-halting" patterns, and only needs to capture trace entries needed to apply its rules. For example, since the rules explicitly ignore trace entries from HHH, HHH doesn't need to capture them. You can see those trace entries in the x86utm LOG, which is why the log is the way to go, when working out what's going on and why.
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Just to be 100% clear for PO's benefit, when I say HHH "only needs to capture trace entries needed to apply its rules" I am not suggesting those rules are correct - just that from a coding perspective, there's no point in a program capturing data that is irrelevent for it's later processing. As an example here, PO adds trace entries to his global trace table which are of no interest to any of his rules! Really, he is only interested in branches, calls, and the likes, but he captures everything DDD does like "mov ebp,esp" or whatever which his rules all ignore... Not an issue in practice because his trace captures [given other filtering] are tiny. Might become important for capacity reasons if PO wanted to include HHH entries, but he doesn't.
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Now, anyone thinking sensibly at this point is going to ask *WHY* does PO's rule
*exclude conditional branches within HHH* when they are obviously critical to halting? PO will never explain that.
*I have always explained that and everyone ignores my explanation*
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On 8/2/2024 11:32 PM, Jeff Barnett wrote:
> ...In some formulations, there are specific states
> defined as "halting states" and the machine only
> halts if either the start state is a halt state...
>
> ...these and many other definitions all have
> equivalent computing prowess...
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Now I have the same basis that I have repeated many
times that cannot be so easily rejected out-of-hand.
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void DDD()
{
HHH(DDD);
return;
}
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*DDD correctly emulated by HHH cannot possibly reach its*
*own "return" instruction final halt state, thus never halts*
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Which is only correct if HHH actuallly does a complete and correct emulation, or the behavior DDD (but not the emulation of DDD by HHH) will reach that return.
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been a contradiction in terms.
HHH correctly predicts that a correct and unlimited emulationAnd is wrong. Since a CORRECT emulation of the DDD that calls THAT HHH, which IS the DDD that is given to that HHH, will see the DDD call the HHH, then it emulating for the number of steps that it emulaltes, then aborting its emulation of the copy of DDD it is working on, then returning to the DDD that is being correctly and completely emulated and then that DDD halting.
of DDD by HHH cannot possibly reach its own "return" instruction
final halt state.
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>No, but it is required to determine what such an emulation would do.
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D would never
stop running unless aborted then
H has never ever been required to do an unlimited emulation of
a non-halting input. H has only ever been required to correctly
predict what the behavior of a unlimited emulation would be.
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