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On 8/15/2024 2:00 AM, joes wrote:But that is not an excuess to give the wrong answer.Am Wed, 14 Aug 2024 16:07:43 +0100 schrieb Mike Terry:On 14/08/2024 08:43, joes wrote:>Am Tue, 13 Aug 2024 21:38:07 -0500 schrieb olcott:On 8/13/2024 9:29 PM, Richard Damon wrote:>On 8/13/24 8:52 PM, olcott wrote:You were trying to label an incomplete/partial/aborted simulation asThat is what I said dufuss.A simulation of N instructions of DDD by HHH according to theNope, it is just the correct PARTIAL emulation of the first N
semantics of the x86 language is necessarily correct.
instructions of DDD, and not of all of DDD,
correct.
>how *HHH* returns*Try to show exactly how DDD emulated by HHH returns to its caller*A correct simulation of N instructions of DDD by HHH is sufficientNope, if a HHH returns to its caller,
to correctly predict the behavior of an unlimited simulation.DDDHHH simulates DDD enter the matrix
DDD calls HHH(DDD) Fred: could be eliminated HHH simulatesvoilasecond level
DDD calls HHH(DDD) recursion detected
HHH aborts, returns outside interference DDD haltsHHH halts>
You're misunderstanding the scenario? If your simulated HHH aborts its
simulation [line 5 above],
then the outer level H would have aborted its identical simulation
earlier. You know that, right?Of course. I made it only to illustrate one step in the paradoxicalIt is like I always pointed out. The outer HHH cannot
reasoning, as long as we're calling programs that do or don't abort
the same.
>
wait for the inner ones to abort because it would be
waiting forever.
You either understand this or do not understand Mike's
correction.
So your trace is impossible...Just like all the others are wrong.
>
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