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On 8/31/2024 9:59 AM, Fred. Zwarts wrote:Op 31.aug.2024 om 14:03 schreef olcott:On 8/31/2024 4:07 AM, Fred. Zwarts wrote:Op 30.aug.2024 om 16:58 schreef olcott:On 8/30/2024 9:56 AM, joes wrote:Am Thu, 29 Aug 2024 09:07:39 -0500 schrieb olcott:
^ importantHere is your problem. The code of the program and its meaning*This is before any aborting occurs*HHH correctly predicts what the behavior of DDD would be if thisProblem is, DDD is then not calling itself, but the non-input of a
HHH never aborted its emulation of DDD.
not-aborting HHH.
according to the semantics of the x86 language, does not suddenly
change when the aborting occurs.
You cannot possibly say one damn thing about the behavior of DDD untilAnd when this unmodified world class x86 simulator was given olcott's
you first understand that a world class x86 emulator that HHH calls
does enable HHH to correctly emulate itself emulating DDD and the
following execution trace proves this.
DDD based on the aborting HHH as input, it showed that this has halting
behaviour.
THIS IS A VERIFIED FACT! Even olcott has verified it.
This correct simulation by the unmodified world class simulator tells
us that the program has a halting behaviour.
Your *modification* of the simulator stops the simulation before it can
see the halting behaviour and decides that the input is non-halting.
We know which one is correct: the unmodified world class simulator, not
the *modified* one, which aborts one cycle too soon..
The fourth instruction (the call) encompasses quite a few furtherStill dreaming of the HHH that does an infinite recursion?Before we can proceed to the next step you must first agree that the
second emulation of DDD by the emulated HHH is proven to be correct on
the basis that it does emulate the first four instructions of DDD.
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