Liste des Groupes | Revenir à c theory |
On 11/18/2024 3:19 AM, joes wrote:Then your arguement is based on an equivocation.Am Sun, 17 Nov 2024 20:35:43 -0600 schrieb olcott:No I do not mean that.On 11/17/2024 8:26 PM, Richard Damon wrote:>On 11/17/24 8:44 PM, olcott wrote:On 11/17/2024 4:03 PM, Richard Damon wrote:On 11/17/24 3:49 PM, olcott wrote:On 11/17/2024 1:56 PM, Richard Damon wrote:On 11/17/24 1:36 PM, olcott wrote:>I referred to every element of an infinite set of encodings of HHH.
Do you mean they are parameterised by the number of steps they simulate?
>
Whether or not DDD emulated by HHH ever reaches itsExcept that the behavior DOES depend on if that HHH returns.
own "return" instruction final halt state has nothing
to do with any of the internal working of HHH as long
as each HHH emulates N steps of its input according
to the semantics of the x86 language.
But that it the definition of Non-Halting.It is ridiculously stupid to require a non-halting input to be>When each of them correctly emulates N instructions of its input
then N instructions have been correctly emulated. It is despicably
dishonest of you to say that when N instructions have been correctly
emulated that no instructions have been correctly emulating.
Then not all instructions have been simulated correctly.
emulated completely because of the requirement that HHH itself
must halt.
All emulating termination analyzers are required to correctlyRight, and they need to be CORRECT, and the emulation they are predictiong is NOT their own (unless that *IS* unbounded).
PREDICT whether or not an unlimited emulation of their input
would cause their own non-termination.
When someone (that knows better) insists that this emulationNope, YOU make the jackass of yourself by saying definitions don't matter.
must be complete they merely make a complete jackass of themselves.
And your HHH violates the design requirement that the answer matches the unbounded emulaiton of the input.>The violates the design requirement that an emulating termination>>No, but it is the fact that it CAN be emulated for an unbounded numberI never said that N instructions correctly emulated is no
instructions correctly emulated, just that it isn't a correct
emulation that provides the answer for the semantic property of
halting, which requires emulating to the final state or an unbounded
number of steps.
of steps that makes it non-halting.
It cannot be emulated for an unbounded number of steps.
???
You can continue to simulate an infinite loop forever.
>
analyzer must itself halt.
Les messages affichés proviennent d'usenet.