Re: HHH(DDD) computes the mapping from its input to HHH emulating itself emulating DDD

On 11/28/2024 10:27 AM, joes wrote:

Am Thu, 28 Nov 2024 10:16:15 -0600 schrieb olcott:

On 11/28/2024 4:04 AM, joes wrote:

Am Wed, 27 Nov 2024 19:15:41 -0600 schrieb olcott:

On 11/27/2024 8:03 AM, Richard Damon wrote:

On 11/27/24 8:28 AM, olcott wrote:

On 11/27/2024 6:14 AM, Richard Damon wrote:

olcott <NoOne@NoWhere.com> wrote:

On 11/26/2024 7:02 AM, Richard Damon wrote:

On 11/25/24 11:08 PM, olcott wrote:

On 11/24/2024 11:18 AM, Richard Damon wrote:

On 11/24/24 9:30 AM, olcott wrote:

On 11/23/2024 11:54 AM, Richard Damon wrote:

On 11/23/24 11:54 AM, olcott wrote:

On 11/23/2024 9:35 AM, Richard Damon wrote:

On 11/23/24 10:15 AM, olcott wrote:

On 11/23/2024 9:02 AM, Richard Damon wrote:

On 11/23/24 9:04 AM, olcott wrote:

On 11/23/2024 1:59 AM, Mikko wrote:

On 2024-11-22 16:45:52 +0000, olcott said:

On 11/22/2024 2:30 AM, Mikko wrote:

On 2024-11-21 15:32:38 +0000, olcott said:

On 11/21/2024 3:12 AM, Mikko wrote:

On 2024-11-20 22:03:43 +0000, olcott said:

On 11/20/2024 3:53 AM, Mikko wrote:

On 2024-11-20 03:23:12 +0000, olcott said:

On 11/19/2024 4:12 AM, Mikko wrote:

On 2024-11-18 20:42:02 +0000, olcott said:

On 11/18/2024 3:41 AM, Mikko wrote:

On 2024-11-17 18:36:17 +0000, olcott said:

>

When DDD is emulated by HHH and DDD calls HHH(DDD) this call never
returns.

That's weird. Why can't HHH simulate itself?

I have already told you and conclusively proven that HHH does emulate
itself emulating DDD. I have told you this dozens of times and my code
continues to prove this.

 

I don't get it. HHH clearly halts in order to return a value. But that
value is "doesn't halt". Why does HHH, which does only a partial
simulation, report that itself (called by DDD) doesn't halt?
>

 https://github.com/plolcott/x86utm
You just may not have the required software engineering
skill to get it. If you did then you could just carefully
study the code and see.