Re: DD specifies non-terminating behavior to HHH --- COMPLETE PROOF

On 2/25/2025 10:13 AM, Mikko wrote:

Althogh the subject line has the words "COMPLETE PROOF" there is no
proof or pointer to proof below.
 

typedef void (*ptr)();
int HHH(ptr P);
int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}
int main()
{
   HHH(DD);
}
The above does specify that DD simulated by HHH
cannot possibly terminate normally by reaching its
own "return" instruction.
That this may be beyond your technical skill level.
is less than no rebuttal at all.
Ignoring the code in main() seemed dishonest.
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer