Re: Anyone with sufficient knowledge of C knows that DD specifies non-terminating behavior to HHH

Op 27.feb.2025 om 06:04 schreef olcott:

On 2/26/2025 5:53 PM, Richard Damon wrote:

On 2/26/25 9:45 AM, olcott wrote:

On 2/26/2025 3:29 AM, joes wrote:

Am Tue, 25 Feb 2025 20:13:43 -0600 schrieb olcott:

On 2/25/2025 5:41 PM, Richard Damon wrote:

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The behavior of DD emulated by HHH only refers to DD and the fact that
HHH emulates this DD.

On on hand, the simulator can have no influence on the execution.

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On the other, that same simulator is part of the program.
You don't understand this simple entanglement.
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Unless having no influence causes itself to
never terminate then the one influence that
it must have is stopping the emulation of this input.
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But it isn't an EXTERNAL influnce, but the behavior of the code of the program itself, in the code of HHH that DD calls, which *IS* part of DD.
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You are just proving you don't kno

 We are asking can DD emulated by HHH possibly reach its
own return instruction?
 Dishonest dodges away from this point are less than no rebuttal at all.
 

This question is already a dodge away. If the answer is 'No, HHH cannot reach the end of this terminating program', then it only proves the failure of HHH to reach the end of a terminating program. It does not say anything about the behaviour of DD.
We agreed already that HHH fails to reach the end of the simulation, so, I wonder why Olcott does not continue to the next step.