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On 2/26/2025 5:53 PM, Richard Damon wrote:This question is already a dodge away. If the answer is 'No, HHH cannot reach the end of this terminating program', then it only proves the failure of HHH to reach the end of a terminating program. It does not say anything about the behaviour of DD.On 2/26/25 9:45 AM, olcott wrote:We are asking can DD emulated by HHH possibly reach itsOn 2/26/2025 3:29 AM, joes wrote:>Am Tue, 25 Feb 2025 20:13:43 -0600 schrieb olcott:>On 2/25/2025 5:41 PM, Richard Damon wrote:
>>The behavior of DD emulated by HHH only refers to DD and the fact thatOn on hand, the simulator can have no influence on the execution.
HHH emulates this DD.On the other, that same simulator is part of the program.>
You don't understand this simple entanglement.
>
Unless having no influence causes itself to
never terminate then the one influence that
it must have is stopping the emulation of this input.
>
But it isn't an EXTERNAL influnce, but the behavior of the code of the program itself, in the code of HHH that DD calls, which *IS* part of DD.
>
You are just proving you don't kno
own return instruction?
Dishonest dodges away from this point are less than no rebuttal at all.
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