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On 3/1/25 5:02 PM, olcott wrote:I don't have time left to talk in circlesOn 3/1/2025 2:10 AM, Mikko wrote:Which is just a strawman, proving that you are just a fraud.On 2025-03-01 01:16:41 +0000, olcott said:>
>On 2/28/2025 3:16 AM, Mikko wrote:>On 2025-02-27 15:29:31 +0000, olcott said:>
>>>No, it is correct to report that HHH is unable to correctly simulate this halting program up to its end.>
In other words you are totally clueless that infinite
recursion HAS NO END.
Do you mean that having no end enables the simulation to the end?
see my new post
DD emulated by HHH cannot possibly terminate normally --- x86 code
In that post:
>DD()>
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
>
When we hypothesize that the code at machine address
0000213c is an x86 emulator then we know that DD
remains stuck in recursive emulation and cannot possibly
reach its own "ret" instruction and terminate normally.
>
When we add the additional complexity that HHH also
aborts this sequence at some point then every level
of recursive emulation immediately stops. This does
not enable any DD to ever reach its "ret" instruction.
The question remains unanswered. If the author cannot tell what he
means we may assume that he didn't mean anything.
>
Your question applied to my ambiguous verbiage.
I cancel that ambiguous verbiage and say that
DD emulated by HHH cannot possibly reach its
own "ret" instruction.
>
>
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