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On 3/13/2025 4:22 AM, Mikko wrote:Which isn't a program, since it doesn't include the code for HHH.On 2025-03-13 00:36:04 +0000, olcott said:_DDD()
>>>
void DDD()
{
HHH(DDD);
return;
}
>
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
>
When HHH correctly emulates N steps of the
above functions none of them can possibly reach
their own "return" instruction and terminate normally.
Nevertheless, assuming HHH is a decider, Infinite_Loop and Infinite_Recursion
specify a non-terminating behaviour, DDD specifies a terminating behaviour
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
What is the sequence of machine languageThat is a nonsense question, since your DDD isn't a program, and thus can't be correctly emulated beyond the call HHH instruction.
instructions of DDD emulated by HHH such that DDD
reaches its machine address 00002183?
Any failure to answer with the sequence of machineNo, your failure to understand the meaning of the words you use, and your admittion that =your whole argument is based on the FRAUD of redefining core terms to non-sense and thus evrything is just based on non-sensical strawmen, shows how utterly stupid you are.
addresses will be construed as
YOU KNOW THAT YOU ARE LYING OR DON'T UNDERSTAND THE QUESTON
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