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On 3/20/2025 8:31 PM, Richard Damon wrote:Right, and you still don't understand that you are required to follow the definitions of the system to be in the system.On 3/20/25 6:43 PM, olcott wrote:We have been over this same thing too many times.On 3/20/2025 4:16 AM, Mikko wrote:>On 2025-03-20 02:32:43 +0000, olcott said:>
>DDD()>
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
>
When N steps of DDD are emulated by HHH according
to the semantics of the x86 language then these
N steps are emulated correctly.
That does not make much sense to define the correct emulation of DDD as
it should mean whatever "correct emulation" means when applied to DDD.
>
Althouth promised otherwise on the subject line the meaning of "DDD
correctly emulated by HHH" when N is not specified is not defined.
>
N in this context always means any element of the
set of natural numbers.
Then HHH isn't a specific program, and you are admitting that you "logic" is just based on FRAUD.
>
In other words, you claim it is ok to lie about the system you are working on.The point remains the same without the additional details.>>
1,2,3...4,294,967,296 steps of DDD are correctly emulated
by HHH and DDD never reaches its "ret" instruction and
terminates normally.
DIFFERENT HHHs and thus DIFFERENT DDDs were emulated.
>
For every HHH at machine address 000015d2 when the above
listed machine code is emulated for any finite number of
steps according to the semantics of the x86 language the
above finite string of machine code never reaches its own
"ret" instruction and halts.
But of something that isn't a program, and thus a type error.Same finite string at the same machine address 00002172.>>The term should be or include "partial emulation" when the intent is>
that an emulation that could be continued is not is called "correct".
>
A finite number of N steps means a finite emulation.
>
Right, and every one of them creates an input DDD,
Because they are different FACTS.that when COMPLETELY emulated halts,You already said that DDD emulated by HHH never reaches
its own "ret" instruction in any finite number of steps,
WHY LIE ABOUT THIS NOW?
Yes, why do you lie?and thus should be called a halting input in any HONEST logic system.WHY LIE ABOUT THIS NOW?
>
Of course, in your FRAUD, you claim otherwise, but that just shows how bad your FRAUDULANT system is,
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