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On 4/2/2025 9:10 AM, joes wrote:However, the correct answer is the same in both cases. Both DDD thatAm Mon, 31 Mar 2025 18:34:17 -0500 schrieb olcott:On 3/31/2025 5:54 PM, dbush wrote:No, it is YOUR misconception. The algorithm DDD consists of theWe have already been over this.
function DDD, the function HHH, and everything that HHH calls down to
the OS level.
HHH(DDD) and HHH1(DDD) have the same inputs all the way down to the OS
level. The ONLY difference is that DDD does not call HHH1(DDD) in
recursive emulation.That is actually not a difference but the same that DDD calls HHH.That DDD calls HHH(DDD) instead of HHH1(DDD)
causes the behavior of DDD emulated by HHH and
DDD emulated by HHH1 to differ.
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