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On 4/28/2025 3:13 PM, Richard Heathfield wrote:
No, H gets P(D) as input, not itself. H is the "measurer", not beingWhat matters is whether a TM can be constructed that can accept anYet it is H(P,D) and NOT P(D) that must be measured. Computer science
arbitrary TM tape P and an arbitrary input tape D and correctly
calculate whether, given D as input, P would halt. Turing proved that
such a TM cannot be constructed.
This is what we call the Halting Problem.
has been wrong about this all of these years. When I provide the 100%
concrete example of the x86 language there is zero vagueness to slip
through the cracks of understanding.
Even calling the Turing Machine language the Turing Machine descriptionThe what? Who called it that?
language make this confusing.
*This is a verified fact*DD doesn't do anything, it is just data. HHH is the active part.
When DD is emulated by HHH according to the finite string transformation
rules of the x86 language DD cannot possibly reach its own final state
no matter what HHH does.
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