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On 5/4/2025 2:01 PM, Richard Heathfield wrote:DD is NOT correctly emulated by HHH, and thus you just prove yourself to be a pathological iiar.On 04/05/2025 18:30, olcott wrote:ONLY IF YOU STUPIDLY IGNORE THE X86 LANGUAGEOn 5/4/2025 11:21 AM, Richard Heathfield wrote:<snip>On 04/05/2025 17:06, olcott wrote:>
>
<snip>
>They simply guess that because DD(DD) halts that>
DD correctly simulated by HHH must also halt.
It's not a guess. If direct execution halts, so must the simulation.>>
Maybe you are confused between halting (reaching
a final halt state and terminating normally)
with stopping running for any reason such as
an aborted emulation. *THEY ARE NOT THE SAME*
Maybe you are confused between equality and inequality.
>
If DD halts when directly executed, then a correct simulation of DD must also halt.
THAT PROVES THAT DD CORRECTLY EMULATED BY HHH IS
NOT THE SAME EXECUTION TRACE AS DIRECTLY EXECUTED DD(DD)
_DD()
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
After DD is correctly emulated by HHH
HHH MUST EMULATE ITSELF EMULATING DD
OR IT VIOLATES THE RULES OF THE X86 LANGUAGE.
The relationshop between HHH and DD is the exactNo, because HHH does exactly the same thing for both, as it never sees far enough to tell the difference, and thus HHH always returns 0 to its caller, and thus both DD and DDD will halt.
same infinite recursion as the above HHH and DDD
except that HHH is smart enough to cut it off
and not get stuck in infinite recursion.
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