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On 5/10/2025 11:00 AM, wij wrote:<snip>On Sat, 2025-05-10 at 10:43 -0500, olcott wrote:On 5/10/2025 10:14 AM, wij wrote:
No, it's not. It's a pointer to function.The input to HHH(DDD) is a pointer to a finite string>H reads a *pointer*.>
In P, P *calls* H.
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Both do not process 'finite string'.
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What it is it a pointer to a box of chocolates?
finite strings are passed as pointers to finite
string in C.
Nope. I don't believe it is a pointer to chocolates, even if you say so.
It is about the code of D/H itself. They do not process string, the fact says
the author of the program does not intend to process 'string'.
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of machine code.
HHH applies an x86 emulator to thisNo, HHH casts P's value to uint32_t (which is legal) and then dereferences it (which is not). There is no string to apply anything to.
finite string.
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