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On 5/12/2025 8:56 PM, olcott wrote:Exactly what actual reasoning shows that thisOn 5/12/2025 7:36 PM, dbush wrote:It makes sense because that's what's required to tell me if any arbitrary algorithm X with input Y will halt when executed directly.On 5/12/2025 8:34 PM, olcott wrote:>On 5/12/2025 7:27 PM, dbush wrote:>On 5/12/2025 8:25 PM, olcott wrote:>On 5/12/2025 7:12 PM, dbush wrote:>On 5/12/2025 7:53 PM, olcott wrote:>>>
Simulating Termination analyzers cannot possibly report
on the actual behavior of non-terminating inputs
because this would cause themselves to never terminate.
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They must always hypothesize what the behavior of the
input would be if they themselves never aborted.
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False. They must always hypothesize what the behavior of algorithm described by the input would be if it was executed directly, as per the requirements:
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Show the actual reasoning of how it makes sense
that a simulating termination analyzer should
ignore the behavior (to its own peril) that the
input actually specifies.
There is no requirement that building a termination analyzer, simulating or otherwise, is possible. In fact, it has proved to not be possible by Linz and others, which you have *explicitly* agreed with.
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In other words you have no such actual reasoning.
The reasoning is that there is no requirement that building a termination analyzer is possible.
So you have no actual reasoning that addresses my
actual point.
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>>>> Show the actual reasoning of how it makes sense
>>>> that a simulating termination analyzer should
>>>> ignore the behavior (to its own peril) that the
>>>> input actually specifies.
>
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