Sujet : Re: How the requirements that Professor Sipser agreed to are exactly met --- WDH
De : dbush.mobile (at) *nospam* gmail.com (dbush)
Groupes : comp.theoryDate : 14. May 2025, 22:25:53
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <10031p1$2mbr6$14@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
User-Agent : Mozilla Thunderbird
On 5/14/2025 5:01 PM, olcott wrote:
On 5/14/2025 3:51 PM, dbush wrote:
On 5/14/2025 11:45 AM, olcott wrote:
On 5/14/2025 6:20 AM, Richard Damon wrote:
>
And since the DD that HHH is simulating WILL HALT when fully simulated (an action that HHH doesn't do)
>
*NOT IN THE ACTUAL SPEC*
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its
input D until H correctly determines that its simulated D
would never stop running unless aborted then
>
>
That Sipser didn't agree what you think the above means:
>
If that was actually true then you could provide an
alternative meaning for the exact words stated above.
That Ben relayed a statement saying explicitly that is proof enough.
But this is what anyone familiar with the halting problem would think it would mean:
If simulating halt decider H correctly simulates its
input D until H correctly determines that UTM(D)
would never stop running unless aborted then
Because that is what is required:
Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:
A solution to the halting problem is an algorithm H that computes the following mapping:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly