Re: How could HHH report on the behavior of its caller?

On 5/14/2025 9:54 PM, Richard Damon wrote:

On 5/14/25 9:30 PM, olcott wrote:

void DDD()
{
   HHH(DDD);
   return;
}
>
int main()
{
   DDD();
}
>
If HHH cannot report on the behavior of its caller
because this is a ridiculous requirement then how
can HHH report on the direct execution of DDD()
(AKA its caller).
>

 Because it is given the code of DDD, and thus doesn't need to know about "It caller"
 

Unless it does know about its caller
The only directly executed DDD() that actually exists
no HHH can possibly know about any directly executed DDD().
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer