Re: How the requirements that Professor Sipser agreed to are exactly met --- WDH

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Sujet : Re: How the requirements that Professor Sipser agreed to are exactly met --- WDH
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theory
Date : 15. May 2025, 12:04:36
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <1004ho4$331gh$7@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
User-Agent : Mozilla Thunderbird
Op 15.mei.2025 om 01:57 schreef olcott:
On 5/14/2025 6:43 PM, Keith Thompson wrote:
olcott <polcott333@gmail.com> writes:
[...]
HHH does correctly simulate DDD until
HHH correctly determines that its simulated DDD
would never stop running unless aborted.
[...]
>
And my understanding is that it is mathematically impossible for HHH
to do what you claim it does,
 That is ridiculous as you already acknowledged.
 void DDD()
{
   HHH(DDD);
   return;
}
 It is dead obvious to any expert in C to correctly
determine that DDD cannot possibly stop running
when HHH is a pure simulator.
 HHH merely needs to see this exact same DEAD OBVIOUS thing.
 >
Claiming and shouting is not proving. It is dead obvious that HHH fails to reach the reachable end of the program, because HHH fails to see the most important part of its input, the part that aborts. That the programmer made HHH blind for that part of the input, does not mean that it is not present.

Date Sujet#  Auteur
9 Jan 26 o 

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