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On 2025-06-02 15:52:53 +0000, olcott said:No they do not. When DDD calls its own emulator its behavior
DDD correctly emulated by HHH diverges from DDDThe DDD emulated (correctly or otherwise) by HHH is the same DDD as
correctly emulated by HHH1 as soon as HHH begins
emulating itself emulating DDD, marked below.
the one emulated (correctly or otherwise) so both specify the same
behaviour.
As soon as the emulations diverge (if not even sooner)--
at lest one of the emulators is no longer emulating correctly.
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