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On 6/4/2025 10:36 PM, olcott wrote:*besides side-by-side IS NOT SIDE-BY-SIDE*On 6/4/2025 9:10 PM, dbush wrote:False. That is *exactly* how they are made. Anything that the directly executed HHH1 emulates, at any level,On 6/4/2025 10:06 PM, olcott wrote:>On 6/4/2025 8:48 PM, dbush wrote:>On 6/4/2025 9:39 PM, olcott wrote:>On 6/4/2025 8:28 PM, dbush wrote:>>
DDD emulated by HHH1 emulating HHH DDD emulated by HHH emulating HHH
[00002183] push ebp ; [00002183] push ebp ;
[00002184] mov ebp,esp ; [00002184] mov ebp,esp ;
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
### HHH aborts ###
>
*That is dishonest*
No, that is the *fact* of what happens when HHH1 emulates DDD
>HHH1 emulates DDD once and this matchesThe one time that the outer HHH emulates DDD, up to the point that HHH aborts
>>>
DDD emulated by HHH1 DDD emulated by HHH
[00002183] push ebp [00002183] push ebp
[00002184] mov ebp,esp [00002184] mov ebp,esp
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
>
*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
False. HHH1 is still simulating the left side by simulating HHH as shown above.
>
The is not the way that side-by-side comparisons of
DDD simulated by HHH1 versus DDD simulated by HHH
are made.
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