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On 6/4/25 10:40 PM, olcott wrote:*HHH is simulated THREE TIMES* Why lie ?On 6/4/2025 8:53 PM, Richard Damon wrote:No, your traces show exactly the opposite.On 6/4/25 11:40 AM, olcott wrote:>On 6/4/2025 6:22 AM, Richard Damon wrote:>On 6/3/25 10:51 PM, olcott wrote:>On 6/3/2025 9:42 PM, dbush wrote:>On 6/3/2025 10:29 PM, olcott wrote:>On 6/3/2025 8:57 PM, dbush wrote:>On 6/3/2025 5:14 PM, olcott wrote:>On 6/3/2025 3:48 PM, joes wrote:>Am Tue, 03 Jun 2025 14:47:23 -0500 schrieb olcott:>On 6/3/2025 3:28 AM, Fred. Zwarts wrote:>Op 02.jun.2025 om 17:52 schreef olcott:>DDD correctly emulated by HHH diverges from DDD correctly emulated by
HHH1 as soon as HHH begins emulating itself emulating DDD, marked
below.
*HHH1 never emulates itself emulating DDD*>*This is the beginning of the divergence of the behavior*
*of DDD emulated by HHH versus DDD emulated by HHH1*Yes, that is exactly the point where HHH aborts.Misleading words when you change the meaning of diverging.>
Mike showed the traces side by side. Even after many requests, you
still cannot show the first instruction that is interpreted differently
by HHH and HHH1. The only difference is that HHH gives up the
simulation too early.
As soon as HHH begins emulating itself and HHH1 NEVER begins emulating
itself THIS IS THE DIVERGENCE.
Both the divergence and the abort are shown below.
>
_DDD()
[00002183] 55 push ebp
[00002184] 8bec mov ebp,esp
[00002186] 6883210000 push 00002183 ; push DDD
[0000218b] e833f4ffff call 000015c3 ; call HHH
[00002190] 83c404 add esp,+04
[00002193] 5d pop ebp
[00002194] c3 ret
Size in bytes:(0018) [00002194]
>
_main()
[000021a3] 55 push ebp
[000021a4] 8bec mov ebp,esp
[000021a6] 6883210000 push 00002183 ; push DDD
[000021ab] e843f3ffff call 000014f3 ; call HHH1
[000021b0] 83c404 add esp,+04
[000021b3] 33c0 xor eax,eax
[000021b5] 5d pop ebp
[000021b6] c3 ret
Size in bytes:(0020) [000021b6]
>
machine stack stack machine assembly
address address data code language
======== ======== ======== ========== =============
[000021a3][0010382d][00000000] 55 push ebp ; main()
[000021a4][0010382d][00000000] 8bec mov ebp,esp ; main()
[000021a6][00103829][00002183] 6883210000 push 00002183 ; push DDD
[000021ab][00103825][000021b0] e843f3ffff call 000014f3 ; call HHH1
New slave_stack at:1038d1
>
Begin Local Halt Decider Simulation Execution Trace Stored at:1138d9
[00002183][001138c9][001138cd] 55 push ebp ; DDD of HHH1
[00002184][001138c9][001138cd] 8bec mov ebp,esp ; DDD of HHH1
[00002186][001138c5][00002183] 6883210000 push 00002183 ; push DDD
[0000218b][001138c1][00002190] e833f4ffff call 000015c3 ; call HHH
New slave_stack at:14e2f9
>
Begin Local Halt Decider Simulation Execution Trace Stored at:15e301
[00002183][0015e2f1][0015e2f5] 55 push ebp ; DDD of HHH[0]
[00002184][0015e2f1][0015e2f5] 8bec mov ebp,esp ; DDD of HHH[0]
[00002186][0015e2ed][00002183] 6883210000 push 00002183 ; push DDD
[0000218b][0015e2e9][00002190] e833f4ffff call 000015c3 ; call HHH
New slave_stack at:198d21
>
THIS IS WHERE THE DIVERGENCE OF DDD EMULATED BY HHH
AND DDD EMULATED BY HHH1 BEGINS
So how exactly do HHH and HHH1 emulate the first instruction of HHH differently?
>
The question is incorrect.
HHH emulates DDD two times and HHH1 emulates DDD one time
the whole second time is the divergence.
There is no divergence if the instructions are emulated exactly the same in both cases.
HHH1(DDD) emulates DDD exactly one time.
HHH(DDD) emulates DDD exactly two times.
>
The whole second time that HHH emulates DDD is
divergence.
>
You mean it INCORRECT imagining of what it THINKS HHH should do because it thinks that HHH is just a correct simulator?
>
The question is:
At exactly what point does DDD simulated by HHH
diverge from DDD simulated by HHH1?
Right, which x86 instruction, correctly simulated, had differing results.
>>>
As soon as HHH simulates itself simulating DDD it is
simulating DDD one more time than DDD simulated by
HHH1 ever gets to.
>
In other words, your idea of "simulation per the language of the x86 language" isn't actually based on actually emulating the actual x86 instrucitons, but instead presuming that HHH is just a pure simulator that never aborts, and then you let it abort.
>
Counter-factual.
HHH simulates DDD exactly twice
HHH1 simulates DDD exactly once
>
Dennis Bush does not seem to understand that 1 != 2
>
HHH simuated DDD once,
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