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On 6/5/2025 6:37 AM, Richard Damon wrote:And the simulated simulated HHH is being simulated by HHH1, and thus in ITS processing.On 6/4/25 10:06 PM, olcott wrote:The above is not an emulation done by HHH1On 6/4/2025 8:48 PM, dbush wrote:>On 6/4/2025 9:39 PM, olcott wrote:>On 6/4/2025 8:28 PM, dbush wrote:>>
DDD emulated by HHH1 emulating HHH DDD emulated by HHH emulating HHH
[00002183] push ebp ; [00002183] push ebp ;
[00002184] mov ebp,esp ; [00002184] mov ebp,esp ;
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
### HHH aborts ###
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*That is dishonest*
HHH1 emulates DDD once and this matches
the first time that HHH emulates DDD.
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DDD emulated by HHH1 DDD emulated by HHH
[00002183] push ebp [00002183] push ebp
[00002184] mov ebp,esp [00002184] mov ebp,esp
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
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*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
Right, becuase HHH gives up when HHH1 proves that the complete emulation would halt.
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*Then DDD emulated by HHH diverges from DDD emulated by HHH1*
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DDD emulated by HHH emulating itself
[00002183] push ebp ;
[00002184] mov ebp,esp ;
[00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH
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Which is the emulation done by HHH1, that shows that HHH will abort and return 0 and thus DDD halts.
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it is done by a simulated simulated HHH.
You have to keep the basic facts straightYou need to follow your own advice,
or you will never understand.
Which goes against the INCORRECT assumptions that HHH used, and thus HHH was just incorrect, and you are proven to not understand how logic works,
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