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On 6/11/2025 9:34 AM, joes wrote:It does. What you try to explain might be correct but what you actuallyAm Wed, 11 Jun 2025 08:55:37 -0500 schrieb olcott:I may be bad at explaining, that does not make me incorrect.On 6/11/2025 7:38 AM, Fred. Zwarts wrote:Op 10.jun.2025 om 19:25 schreef olcott:On 6/10/2025 3:49 AM, Fred. Zwarts wrote:Op 09.jun.2025 om 16:39 schreef olcott:On 6/9/2025 5:26 AM, Fred. Zwarts wrote:That is the interesting part to me. Can somebody formalise or generaliseIndeed, it shows that simulation is not the right way to try to
refute the proof of the halting theorem, because a simulator will
never be able to simulate itself correctly up to the end.
this statement?
What does HHH(HHH) return?So you aren't bright enough to understand that infinite recursion doesRunning one more cycle is enough to see the simulated abort (unless youIt waiting forever is not long enough (and it is) then your idea aboutIt is ridiculously stupid to require a non-terminating input to beIt is even more stupid to ignore the halting part of the input (with
simulated up to its non-existent end.
a premature abort) and claim it is not halting.
"premature abort" is incorrect.
change the input to another input specifying another program that needs
again another cycle. That other input is only in your dream. The input
specified in Halt7.c is the input we discuss.
not halt on its own.
HHH waits until it sees that its input calls the same function with the
same parameters twice in sequence with no conditional branch inbetween
the beginning of DDD and its call to HHH(DDD). It does not matter that
there are conditional branch instructions in HHH because they cannot be
reached and none of them could possibly enable DDD simulated by HHH to
reach its own "return" statement final halt state.
I have told you this many times and you just aren't bright enough toIt makes you bad at explaining.
understand. That you are ignorant DOES NOT MAKE ME INCORRECT, IT MAKES
YOU INCORRECT.
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