j'aimerais savoir s'il y a un moyen de le simplifier:
from datetime import *
month_days = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30]
push_ups = 0
today = date.today()
day = today.day
month = today.month
if month == 2:
push_ups += month_days[0]
elif month == 3:
push_ups += month_days[0:1]
elif month == 4:
push_ups += month_days[0:2]
elif month == 5:
push_ups += month_days[0:3]
elif month == 6:
push_ups += month_days[0:4]
elif month == 7:
push_ups += month_days[0:5]
elif month == 8:
push_ups += month_days[0:6]
elif month == 9:
push_ups += month_days[0:7]
elif month == 10:
push_ups += month_days[0:8]
elif month == 11:
push_ups += month_days[0:9]
elif month == 12:
push_ups += month_days[0:10]
push_ups += day
print("Aujourd'hui, tu dois faire", push_ups, "pompes")
son but est de compter le combientième jour nous sommes dans l'année, si vous
avez une solution, merci d'avance
| Date | Sujet | # | Auteur | |
| 2 Feb 22 |  Simplifier le programme | 4 | OverSkill | |
| 2 Feb 22 |   Re: Simplifier le programme | 1 | Dominique | |
| 2 Feb 22 |  Re: Simplifier le programme | 2 | overskill | |
| 3 Feb 22 |  Re: Simplifier le programme | 1 | Dominique |
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