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On 6/19/2024 8:46 PM, Frank Krygowski wrote:That's a different problem - no lateral acceleration - but it's valuable for thinking about Bob's original question.So it's logical to treat as identical sorts of vectors both the upward force on a cyclist (fighting gravity) and the lateral force on a turning cyclist (pushing him into a curve). It's the resultant of those two forces against which potential energy is determined. And again, the cyclist's angle is always what's necessary to exactly balance that resultant.REally? This CG:
>
So in that reference frame, there is no reduction in potential energy. The bike+rider's CG is always the same distance above the tire.
https://jacoblund.com/cdn/shop/products/f60bc56d059f05627a4511dcb9495818_1500x.jpg?v=1679657105
is the same as this CG?
https://cycling.today/wp-content/uploads/2017/05/Peter-Sagan-min.jpg
No
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