Sujet : Re: Three rational triples
De : kfl (at) *nospam* KeithLynch.net (Keith F. Lynch)
Groupes : rec.puzzlesDate : 19. Sep 2024, 14:16:57
Autres entêtes
Organisation : United Individualist
Message-ID : <vch4np$lv$1@reader1.panix.com>
References : 1 2 3
User-Agent : trn 4.0-test77 (Sep 1, 2010)
HenHanna <
HenHanna@dev.null> wrote:
Keith F. Lynch wrote:
Since it's been more than a week, and nobody has figured it out:
Each of them has a sum that's equal to its product and is an integer.
i think one person said exactly that.
Who and when? I didn't see any such post.
Is it easy to find them?
No, even though there are infinitely many. Try and find one I
didn't list.
Constraints: All three numbers must be positive, real, and rational,
but not integers.
And of course have to be in simplest form, i.e. 1/2, not 2/4. One
person posted "52/39, 7/6, 9/2" which is of course the same three
numbers as my "9/2, 4/3, 7/6". And he didn't say what property
they had, anyway.
Without any constraints, x,i,-i is always a solution for any x,
if i is the square root of minus one.
How about 2 numbers
Too simple to be interesting. If you want two numbers to have a sum
of S and a product of P, whether or not S=P, the two numbers will be
S + sqrt(S^2 - 4P) and S - sqrt(S^2 - 4P).
-- Keith F. Lynch - http://keithlynch.net/Please see http://keithlynch.net/email.html before emailing me.