Sujet : Re: A Trivial Arithmetic Problem
De : msb (at) *nospam* vex.net (Mark Brader)
Groupes : rec.puzzlesDate : 21. Jun 2025, 07:56:02
Autres entêtes
Organisation : -
Message-ID : <bYWcnXo4r-sfysv1nZ2dnZfqnPudnZ2d@giganews.com>
References : 1
User-Agent : trn 4.0-test76 (Apr 2, 2001)
Carl Ginnow:
Hints : The starting number is 13. After each operation, the result is
a whole number. Use this fact to check answers at each "Divide by"
operation.
Start with an unlucky number for a Friday.
13.
Multiply by the gables on Hawthorn's house.
*7 = 91.
Add the number a stitch in time saves.
+9 = 100.
Add the number of blind mice.
+3 = 103.
Subtract the number of William Pène du Bois' balloons.
(First google.)
-21 = 82.
Add the number of wonders of the world.
+7 = 73.
Subtract the number of miles in Camptown's racetrack.
+5 = 68.
Subtract the number of strings on a violin.
-4 = 64.
Divide by the number of vertices on a regular hexahedron.
/8 = 8.
Add the number of the engine that ran on Chicago line.
(Second google.)
One source says 9, another 999.
+ that = 17 or 1007.
Multiply by the number of gentlemen of Verona.
*2 = 34 or 2014.
Add the atomic number of the element whose symbol is the 25th letter of
the alphabet.
(I thought I knew it, but I did a third google to make sure.)
+39 = 73 or 2053.
Divide by the number of hills of Rome.
/7 = not an integer in either case. I give up.
-- Mark Brader | this takeToronto | "If is shall really tomsb@vex.net | flying I never it." | -- Piglet ("Winnie-the-Pooh", A.A. Milne)My text in this article is in the public domain.