Sujet : Re: A Trivial Arithmetic Problem
De : ilan_no_spew (at) *nospam* hotmail.com (IlanMayer)
Groupes : rec.puzzlesDate : 21. Jun 2025, 14:23:46
Autres entêtes
Organisation : novaBBS
Message-ID : <2e8e2bbd30c372efdd85139f1886e6cd@www.novabbs.com>
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On Sat, 21 Jun 2025 6:56:02 +0000, Mark Brader wrote:
Carl Ginnow:
Hints : The starting number is 13. After each operation, the result is
a whole number. Use this fact to check answers at each "Divide by"
operation.
>
Start with an unlucky number for a Friday.
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13.
>
Multiply by the gables on Hawthorn's house.
>
*7 = 91.
>
Add the number a stitch in time saves.
>
+9 = 100.
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Add the number of blind mice.
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+3 = 103.
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Subtract the number of William Pène du Bois' balloons.
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(First google.)
-21 = 82.
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Add the number of wonders of the world.
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+7 = 73.
82 + 7 = 89
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Subtract the number of miles in Camptown's racetrack.
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+5 = 68.
89 - 5 = 84
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Subtract the number of strings on a violin.
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-4 = 64.
84 - 4 = 80
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Divide by the number of vertices on a regular hexahedron.
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/8 = 8.
80 / 8 = 10
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Add the number of the engine that ran on Chicago line.
>
(Second google.)
One source says 9, another 999.
>
+ that = 17 or 1007.
10 + 9 = 19
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Multiply by the number of gentlemen of Verona.
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*2 = 34 or 2014.
19 * 2 = 38
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Add the atomic number of the element whose symbol is the 25th letter of
the alphabet.
>
(I thought I knew it, but I did a third google to make sure.)
+39 = 73 or 2053.
38 + 39 = 77
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Divide by the number of hills of Rome.
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/7 = not an integer in either case. I give up.
77 / 7 = 11
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