Re: A Trivial Arithmetic Problem

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Sujet : Re: A Trivial Arithmetic Problem
De : ilan_no_spew (at) *nospam* hotmail.com (IlanMayer)
Groupes : rec.puzzles
Date : 21. Jun 2025, 14:23:46
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Organisation : novaBBS
Message-ID : <2e8e2bbd30c372efdd85139f1886e6cd@www.novabbs.com>
References : 1 2
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On Sat, 21 Jun 2025 6:56:02 +0000, Mark Brader wrote:

Carl Ginnow:
Hints : The starting number is 13.  After each operation, the result is
a whole number. Use this fact to check answers at each "Divide by"
operation.
>
Start with an unlucky number for a Friday.
>
13.
>
Multiply by the gables on Hawthorn's house.
>
*7 = 91.
>
Add the number a stitch in time saves.
>
+9 = 100.
>
Add the number of blind mice.
>
+3 = 103.
>
Subtract the number of William Pène du Bois' balloons.
>
(First google.)
-21 = 82.
>
Add the number of wonders of the world.
>
+7 = 73.
82 + 7 = 89

>
Subtract the number of miles in Camptown's racetrack.
>
+5 = 68.
89 - 5 = 84

>
Subtract the number of strings on a violin.
>
-4 = 64.
84 - 4 = 80

>
Divide by the number of vertices on a regular hexahedron.
>
/8 = 8.
80 / 8 = 10

>
Add the number of the engine that ran on Chicago line.
>
(Second google.)
One source says 9, another 999.
>
+ that = 17 or 1007.
10 + 9 = 19

>
Multiply by the number of gentlemen of Verona.
>
*2 = 34 or 2014.
19 * 2 = 38

>
Add the atomic number of the element whose symbol is the 25th letter of
the alphabet.
>
(I thought I knew it, but I did a third google to make sure.)
+39 = 73 or 2053.
38 + 39 = 77

>
Divide by the number of hills of Rome.
>
/7 = not an integer in either case.  I give up.
77 / 7 = 11
--

Date Sujet#  Auteur
20 Jun 25 * A Trivial Arithmetic Problem7Carl G.
21 Jun 25 `* Re: A Trivial Arithmetic Problem6Mark Brader
21 Jun 25  +* Re: A Trivial Arithmetic Problem3IlanMayer
21 Jun 25  i`* Re: A Trivial Arithmetic Problem2David Entwistle
24 Jun 25  i `- Re: A Trivial Arithmetic Problem1IlanMayer
21 Jun 25  `* Re: A Trivial Arithmetic Problem2Carl G.
21 Jun 25   `- Re: A Trivial Arithmetic Problem1Richard Heathfield

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