Sujet : Re: @ SCOS Message Format ?
De : qnivq.ragjvfgyr (at) *nospam* ogvagrearg.pbz (David Entwistle)
Groupes : sci.cryptDate : 24. Feb 2025, 13:56:05
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vphq95$132l4$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
User-Agent : Pan/0.149 (Bellevue; 4c157ba git@gitlab.gnome.org:GNOME/pan.git)
On Mon, 24 Feb 2025 10:28:05 +0000, Richard Heathfield wrote:
That would certainly explain it. Test groups tend to be huge. Let David
post here if he wants us to read his examples.
Apologies. That was rather stupid of me.
Posting the following four lines, which could I think could occur in a
SCOS ciphertext:
57 9)
58 :)
59 ;)
60 <)
The defaults settings of Thunderbird 128.6.Oesr (64-bit) downloads the
correct character sequence, but displays:
57 9)
58 🙂
59 😉
60 <)
Where the 58 and 59 lines include unicode characters and have the
following hex values
0x35 0x38 0x20 0xF0 0x9F 0x99 0x82 0x0A
0x35 0x38 0x20 0xF0 0x9F 0x98 0x89 0x0A
The default settings of Pan (0.149) displays something similar, but
different representations of the smileys.
57 9)
58
59
60 <)
I can turn this (dis)functionality off, but many users new to USENET and
encryption will not be aware of what is happening.
I thiunk an easy compromise is already in place. I'd suggest, as an
introduction, SCOSc, for compatibility with any newsreader, is used
without the punctuation characters. I don't see any issues with that, if
no one finds the idea disagreeable.
On another subject, reading "A12.1 Trigraph Sequences" of the ANSI
standard version of "The C Programming Language", does that apply to
Strings, at preprocessing - where '??=' gets replaced with '#' etc. during
preprocessing? Sorry if this a stupid question - I'm no longer familiar
with C.
-- David Entwistle