Sujet : Re: The lost key
De : chris.m.thomasson.1 (at) *nospam* gmail.com (Chris M. Thomasson)
Groupes : sci.cryptDate : 07. Apr 2025, 21:16:54
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vt1brp$jjpg$1@dont-email.me>
References : 1
User-Agent : Mozilla Thunderbird
On 3/27/2025 12:25 PM, Richard Heathfield wrote:
Here's a challenge for you.
I lost my key, so it's not locked.
[...]
A funny program for the ciphertext:
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def add_char(input_string, increment):
result = []
for char in input_string:
ascii_sum = int(char) + increment
result.append(chr(ascii_sum))
return "".join(result)
input = "2848946260538157918367000863848772571624155941440309147181104105973715236751171631344619365840571789679960410281613417934986777121883758077560638903472467639058855049200348722101154699044086248542415920664015225727415899850657037735752534925855988988353704308168166863736592675374332918563267446593496370465749720916683750171432485759516454914993922696517880445639301838174305259484964231962391422203389205533519311439222811085530388606270980794008927920197026957965757301408456000582523271531688939279895920555612097719886773783452558708547"
inc_val = 48
result = add_char(input, inc_val)
print(result)
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Gets me back to the ciphertext:
2848946260538157918367000863848772571624155941440309147181104105973715236751171631344619365840571789679960410281613417934986777121883758077560638903472467639058855049200348722101154699044086248542415920664015225727415899850657037735752534925855988988353704308168166863736592675374332918563267446593496370465749720916683750171432485759516454914993922696517880445639301838174305259484964231962391422203389205533519311439222811085530388606270980794008927920197026957965757301408456000582523271531688939279895920555612097719886773783452558708547
Still in the weeds.