Re: 80dB now but still needs improvement at 1KHz

"Bill Sloman" <bill.sloman@ieee.org> wrote in message news:vga6jh$suru$1@dont-email.me...

On 4/11/2024 5:31 pm, Jan Panteltje wrote:

On a sunny day (Sun, 3 Nov 2024 23:06:04 -0500) it happened "Edward Rawde"
<invalid@invalid.invalid> wrote in
<vg9h7b$277o$1@nnrp.usenet.blueworldhosting.com>:
>

Simulation isn't fast but if you let it complete and do an FFT on the last 30 seconds, it's 80dB down at all unwanted
harmonics.
There do however seem to be unwanted sidebands close in either side of 1KHz
Any suggestions for improvement?

>
Publish a circuit diagram.
Not that hard to make !

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He did. The .asc file is a circuit diagram. I've looked at it and run the simulation - if only for 200 seconds rather than 300
seconds.
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The FFT says that sine wave is as good as he claims.
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The circuit diagram  doesn't make it clear what it's various parts are there to do - it makes sense to group the components in a
way that lets somebody looking at the circuit diagram get some feel for what the components are doing.
>
And it you are using the LT1994 it makes sense to read the data sheet carefully enough to notice that the Icom pin 2 should be
bypassed with at least 100nF to ground.
>
https://www.analog.com/media/en/technical-documentation/data-sheets/1994fb.pdf

Yes there's no way I would use a part without reading the data sheet.
Pass 1 fount the 0.1uF but I hadn't got around to adding it.
Pass 2 found that I couldn't go above +/- 6V
Pass 3 which I haven't done yet would take a lot more time and I probably won't do it because I doubt I'll be able to build this for
real.

Please see also my reply to Jan.

>
John May's circuit makes it clear that the second FET isn't strictly necessary. There are cheaper ways of getting rid of the
even-order harmonics.

Does his circuit have better performance?
Just curious, it's not a competition.

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I've managed to dig out the precision, full wave rectifier that I used in my circuit, which is a half-wave rectifier to which you
add just enough of the full sine wave to deliver both halves of the sine wave (one of them inverted) at it's output, which calls
for a couple 10k 0.1% thin-film precision resistors on a common substrate, which you can buy off the shelf.
>
--
Bill Sloman, Sydney