Sujet : Re: discharging caps
De : jl (at) *nospam* glen--canyon.com (john larkin)
Groupes : sci.electronics.designDate : 10. Sep 2026, 15:17:24
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <mle5alh23e9seucp1kssldcdgo0avgv6fe@4ax.com>
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On Thu, 10 Sep 2026 01:32:56 +1000, Bill Sloman <
bill.sloman@ieee.org>
wrote:
On 9/09/2026 10:25 pm, Jeroen Belleman wrote:
On 9/9/26 12:44, john larkin wrote:
On Wed, 9 Sep 2026 09:51:57 -0000 (UTC), piglet
<erichpwagner@hotmail.com> wrote:
>
Bill Sloman <bill.sloman@ieee.org> wrote:
On 9/09/2026 5:56 am, john larkin wrote:
On Wed, 9 Sep 2026 03:09:41 +1000, Bill Sloman <bill.sloman@ieee.org>
wrote:
>
On 9/09/2026 1:00 am, john larkin wrote:
On Tue, 8 Sep 2026 17:35:24 +1000, Bill Sloman
<bill.sloman@ieee.org>
wrote:
>
On 8/09/2026 4:52 am, john larkin wrote:
On Mon, 7 Sep 2026 19:33:35 +0100, chrisq <syseng@gfsys.co.uk>
wrote:
>
On 9/7/26 16:18, john larkin wrote:
Suppose we have a box with some big caps inside, for example 0.2
farads that run at about 200 volts. When AC power is off, we
want to
discharge them for several reasons.
>
Putting, say, a 1K resistor across them dissipates 40 watts
and has a
200 second time constant. It will take many tau before the
voltage
gets low enough for people to poke around inside.
>
The ideal discharger would be a constant-current or even
better a
constant-power load, all the way down to zero volts. It would
be dumb,
not switched by some decision circuit or anything fancy like
that.
>
And of course we need several LEDs as warnings that the thing
is hot.
>
>
What sort of design needs 0.2 Farad cap, at 200 volts ?. If
you are
working at that level, put in a cheap relay and a rated heatsink
wirewound resistor to dump the energy, when the power goes off.
Cheap, and lossless as well. Motor drive inverters often have
big resistors to brake the motor.
>
>
John Larkin
Highland Tech Glen Canyon Design Center
Lunatic Fringe Electronics
>
It's a 1500 amp laser driver.
>
The input to our box is DC, from an external power supply.
>
I do want a circuit that's foolproof, that always discharges
the caps
but doen't often go up in flames.
>
A resistor makes an exponential decay which could be a very
long time
to get down to safe levels.
>
But a resistor plus an inductor could give a critically damped
decay,
which would be quite a bit faster. I don't know enough about the
circuit
to be prepared to try to work out how much inductance you'd
need, and
you clearly can't be bothered.
>
Won't be bothered.
>
>
I thought the group might like a circuit design problem once in a
while, a break from politics.
>
But you don't do circuit design, and this sort of question makes it
obvious why you don't.
>
The inductor suggestion is hilarious. Thanks.
>
It's elementary circuit theory, which you should have been taught
and I
had to read about.
>
If you discharge a capacitor through a resistor, the voltage decays
exponentially. If you put an inductor in series with the resistor the
voltage decay is a more complicated function of time. If you chose
the
resistance and the inductance to create a critically damped
circuit, the
voltage across the capacitor will eventually decay more rapidly than
you'd see with just the resistor.
>
Try reading about Laplace transforms. That's a pretty hilarious
suggestion to direct at you, but you are the butt of the joke.
>
Oh, RLC circuits are no mystery.
>
What's funny about the suggestion is the size of the inductor it would
need.
>
Which you haven't worked out. I spent a few minutes last night
trying to
work out what I could buy off the shelf from element-14 (the Australian
branch of Newark) but their web-site has turned cranky in recent
months.
>
The value of the inductance isn't fixed - that and the resistor can be
be chosen to get a critically damped LCR, and I figured that I'd start
playing with an inductor I could buy.
>
You might end up with a non-progressively wound air-cored toroid.
With a
0.2F capacitor the parallel capacitance of the inductor isn't going to
be an issue, and the winding resistance could be your damping resistor.
>
4kJ is a fair bit of energy, but you can get copper quite hot before it
explodes. It wouldn't stay hot for long.
>
>
I havent calculated what ballpark inductance might be required but
is air
core even feasible for that?
>
If it were about the size of a truck maybe.
>
You can estimate the inductance in your head. To discharge 0.2F in,
say 100 seconds, you need 500 ohms. That would of course be the tau of
an exponential decay. Adding an inductor would crisp that up.
>
R*C = 100 seconds so we want L/R to be in that ballpark.
>
100 seconds is a lot too long from a safety point of view
The customer specified 200 seconds. They are a government organization
that has a very pickey safety review team.
I want it really dead in well under 200 seconds, below 1 volt.
John Larkin
Highland Tech Glen Canyon Design Center
Lunatic Fringe Electronics
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