Sujet : Re: Kommen drei Logiker in eine Bar. Der Kellner fragt: "Na, was darfs sein, die Herren? Drei Bier?" Sagt der erste Logiker "Ich weiß nicht"
De : benlizro (at) *nospam* ihug.co.nz (Ross Clark)
Groupes : sci.lang soc.culture.germanDate : 23. Jun 2024, 12:56:07
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v592gv$b1ld$1@dont-email.me>
References : 1 2 3 4 5
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On 23/06/2024 10:39 p.m., Phil Carmody wrote:
Ruud Harmsen <rh@rudhar.com> writes:
Sat, 22 Jun 2024 19:29:14 +0300: Phil Carmody <pc+usenet@asdf.org>
scribeva:
>
Ruud Harmsen <rh@rudhar.com> writes:
Mon, 17 Jun 2024 11:18:24 -0700: HenHanna <HenHanna@devnull.tb>
scribeva:
>
>
Kommen drei Logiker in eine Bar. Der Kellner fragt: "Na, was darfs sein,
die Herren? Drei Bier?" Sagt der erste Logiker "Ich weiß nicht", der
zweite auch "Ich weiß nicht" und der Dritte sagt "Ja"
>
------ is this funny? i don't really get it.
>
0 | 0 | 1 = 1, in Boolean logic.
>
True but irrelevant.
>
~0 & ~0 & 1 = 1 is the boolean logic that applies.
>
What do you mean by ~? Not? How is don't know a not.
~ is indeed not.
Saying "don't know" is the *exclusion* of "no" as a possible state,
because if "no" was this guy's intention he would have correctly
answered "no" rather than "don't know".
Phil
But it also excludes "yes". So is ~1 equivalent to ~0? Why not just ~?