Re: Newton's Gravity

Thomas Koenig il 14/01/2025 09:06:07 ha scritto:

Luigi Fortunati <fortunati.luigi@gmail.com> schrieb:
>

The consequence of all this is that the gravitational force of the
larger body of mass M acts on the entire mass <m> of the smaller body
and this justifies the product m*M of Newton's formula, which
corresponds to the force exerted by the larger mass M on the entire
mass <m>.
 
Instead, the gravitational force of the smaller body of mass <m> cannot
act on the entire body of mass M because M is larger

>
That is a non sequitur if there ever was one.  Why should this be the
case?
>
Think of a mass M as being divided into i smaller submasses (all
with the same mass m_part) and of a mass j of being divided into
m smaller submasses with the same mass m_part. Which submass of M
should not interact all submasses of j?

You can divide the entire mass M of the Earth into as many sub-masses
as you want and it (as a whole) will continue to exert its
gravitational force on the entire mass <m> of my body (from which M*m
derives).

On the other hand, if you divide the mass <m> of my body into as many
sub-masses as you want, it (as a whole) will never be able to exert its
miserable gravitational force on *all* the immense mass <M> of the
Earth but will limit itself to the mass <m> of my room without going
beyond (so: not m*M but m*m).

Luigi Fortunati

[[Mod. note -- You've made a bunch of statements here.  Do you have
any evidence for them?  We do have a fair bit of experimental data
on Newtonian gravitation... are your statements consistent with the
experimental data?
-- jt]]