Re: Elastic Collision

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Sujet : Re: Elastic Collision
De : dr.j.thornburg (at) *nospam* gmail-pink.com (Jonathan Thornburg [remove -color to reply])
Groupes : sci.physics.research
Date : 15. Feb 2026, 01:26:34
Autres entêtes
Message-ID : <mt2.1.4-91499-1771143993@gold.bkis-orchard.net>
References : 1
In article <10mlemh$1pima$1@dont-email.me>, Luigi Fortunati writes:
It's obvious that a body of mass 100m, colliding with a body of mass m,
can only slow down but not stop in place and bounce back!

No, it's not obvious, in fact it's not even always true.  Here's a
specific example where the body of mass 100m *does* bounce back:

Suppose we have
  body A: mass m_A=100 kg, initial velocity v_A1=+1 m/s (moving right)
  body B: mass m_B=1 kg, initial velocity v_B1=-1000 m/s (moving left)
and these bodies have an elastic collision at position x=0 m and t=0 s.

The formulas in the previously-cited Wikipedia article
<https://en.wikipedia.org/wiki/Elastic_collision> give the final
velocities after the collision as:
  v_A2 =  -18.822 m/s       (body A recoils to the left)
  v_B2 = +982.178 m/s      (body B recoils to the right)

But we don't have to trust the Wikipedia article!  We can check for
ourselves whether or not these v_A2 and v_B2 are correct by checking
whether or not both linear momentum and kinetic energy are conserved:

Linear momentum:
  before the collision: m_A*v_A1 + m_B*v_B1 = -900 kg m/s
  after  the collision: m_A*v_A2 + m_B*v_B2 = -900 kg m/s
i.e., linear momentum is conserved.

Kinetic energy:
  before the collision: 1/2 m_A*v_A1^2 + 1/2 m_B*v_B1^2 = 500050 Joules
  after  the collision: 1/2 m_A*v_A2^2 + 1/2 m_B*v_B2^2 = 500050 Joules
i.e., kinetic energy is conserved.

Since we find that these values of v_A2 and v_B2 conserve both linear
momentum and kinetic energy, we know that these are in fact the correct
v_A2 and v_B2 for an elastic collision.

From the initial & final velocities, it's easy to calculate the
bodies' positions:
  t (s)        x_A (m)       x_B(m)
  -3           -3.0        +3000.0
  -2           -2.0        +2000.0
  -1           -1.0        +1000.0
   0            0.0            0.0        (collision happens here)
  +1          -18.822       +982.178
  +2          -37.644      +1964.356
  +3          -56.465      +2946.535

So in this case, yes, a body of mass 100 kg does "bounce back" (final
velociity is of the opposite sign to initial velocity) after colliding
with a body of mass 1 kg. 

--
-- "Jonathan Thornburg [remove -color to reply]" <dr.j.thornburg@gmail-pink.com>
   (he/him; on the west coast of Canada)
   "All models are wrong, but some are useful" -- George E. P. Box

Date Sujet#  Auteur
11 Feb 26 * Elastic Collision15Luigi Fortunati
13 Feb 26 +* Re: Elastic Collision5Luigi Fortunati
13 Feb 26 i+- Re: Elastic Collision1Mikko
13 Feb 26 i+- Re: Elastic Collision1Petri Kaukasoina
13 Feb 26 i+- Re: Elastic Collision1Pierre Asselin
15 Feb 26 i`- Re: Elastic Collision1Luigi Fortunati
15 Feb 26 +- Re: Elastic Collision1Jonathan Thornburg [remove -color to reply]
15 Feb 26 +- Re: Elastic Collision1Jonathan Thornburg [remove -color to reply]
16 Feb 26 `* Re: Elastic Collision7Luigi Fortunati
28 Feb 26  +- Re: Elastic Collision1Luigi Fortunati
28 Feb 26  +- Re: Elastic Collision1Mikko
5 Mar 26  +- Re: Elastic Collision1Luigi Fortunati
8 Mar 26  +- Re: Elastic Collision1Mikko
12 Mar 26  +- Re: Elastic Collision1Luigi Fortunati
16 Mar 26  `- Re: Elastic Collision1Mikko

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